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delete a[i];

main() { struct date; struct student { char name[30]; struct date dob; }stud; struct date { int day,month,year; }; scanf("%s%d%d%d", stud.rollno, &student.dob.day, &student.dob.month, &student.dob.year); }

1 Answers  

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#include<stdio.h> int main() { int x=2,y; y=++x*x++*++x; printf("%d",y); } Output for this program is 64. can you explain how this output is come??

1 Answers  

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main() { if ((1||0) && (0||1)) { printf("OK I am done."); } else { printf("OK I am gone."); } } a. OK I am done b. OK I am gone c. compile error d. none of the above

5 Answers   HCL,

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What are the files which are automatically opened when a C file is executed?

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#define f(g,g2) g##g2 main() { int var12=100; printf("%d",f(var,12)); }

3 Answers  

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I need your help, i need a Turbo C code for this problem.. hope u'll help me guys.? Your program will have a 3x3 array. The user will input the sum of each row and each column. Then the user will input 3 values and store them anywhere, or any location or index, temporarily in the array. Your program will supply the remaining six (6) values and determine the exact location of each value in the array. Example: Input: Sum of row 1: 6 Sum of row 2: 15 Sum of row 3: 24 Sum of column 1: 12 Sum of column 2: 15 Sum of column 3: 18 Value 1: 3 Value 2: 5 Value 3: 6 Output: Sum of Row 1 2 3 6 4 5 6 15 7 8 9 24 Sum of Column 12 15 18 Note: Your program will not necessary sort the walues in the array Thanks..

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What are segment and offset addresses?

2 Answers   Infosys,

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#include<stdio.h> main() { struct xx { int x; struct yy { char s; struct xx *p; }; struct yy *q; }; }

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main() { int i=5,j=6,z; printf("%d",i+++j); }

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main() { int i =10, j = 20; clrscr(); printf("%d, %d, ", j-- , --i); printf("%d, %d ", j++ , ++i); } a. 20, 10, 20, 10 b. 20, 9, 20, 10 c. 20, 9, 19, 10 d. 19, 9, 20, 10

4 Answers   HCL,

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Given an array of characters which form a sentence of words, give an efficient algorithm to reverse the order of the words (not characters) in it.

2 Answers   Wipro,

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main() { int c[ ]={2.8,3.4,4,6.7,5}; int j,*p=c,*q=c; for(j=0;j<5;j++) { printf(" %d ",*c); ++q; } for(j=0;j<5;j++){ printf(" %d ",*p); ++p; } }

1 Answers  

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