Answer / guest

delete a[i];

void main() { static int i=5; if(--i){ main(); printf("%d ",i); } }

1 Answers  

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how to print 1 2 3 4 5 6 7 8 9 10 9 8 7 6 5 4 3 2 1 using any loop(for or while) only once(only 1 loop) and maximum 2 variables using C.

19 Answers   Cap Gemini, Infosys,

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#include<stdio.h> main() { struct xx { int x=3; char name[]="hello"; }; struct xx *s; printf("%d",s->x); printf("%s",s->name); }

3 Answers   Hexaware,

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void main() { printf(“sizeof (void *) = %d \n“, sizeof( void *)); printf(“sizeof (int *) = %d \n”, sizeof(int *)); printf(“sizeof (double *) = %d \n”, sizeof(double *)); printf(“sizeof(struct unknown *) = %d \n”, sizeof(struct unknown *)); }

1 Answers  

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print numbers till we want without using loops or condition statements like specifically(for,do while, while swiches, if etc)!

11 Answers   Wipro,

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main() { char c; int i = 456; clrscr(); c = i; printf("%d", c); } a. 456 b. -456 c. random number d. none of the above

3 Answers   BrickRed, HCL,

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Under linux environment can u please provide a c code for computing sum of series 1-2+3-4+5......n terms and -1+2-3+4-5...n terms..

2 Answers  

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&#8206;#define good bad main() { int good=1; int bad=0; printf ("good is:%d",good); }

2 Answers  

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#define a 10 void foo() { #undef a #define a 50 } int main() { printf("%d..",a); foo(); printf("%d..",a); return 0; } explain the answer

1 Answers  

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Design an implement of the inputs functions for event mode

0 Answers   Wipro,

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#include<stdio.h> void fun(int); int main() { int a; a=3; fun(a); printf("\n"); return 0; } void fun(int i) { if(n>0) { fun(--n); printf("%d",n); fun(--n); } } the answer is 0 1 2 0..someone explain how the code is executed..?

1 Answers   Wipro,

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#include<stdio.h> int main() { int a=3,post,pre; post= a++ * a++ * a++; a=3; pre= ++a * ++a * ++a; printf("post=%d pre=%d",post,pre); return 0; }

3 Answers  

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