Answer / pavan_mustyala

1st printf o/p is 30
2nd printf o/p is 20
3rd printf o/p is 0

Reason: O/p depends on scope of variable.

abcdedcba abc cba ab ba a a

2 Answers  

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void main() { static int i=i++, j=j++, k=k++; printf(“i = %d j = %d k = %d”, i, j, k); }

3 Answers  

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main() { static char names[5][20]={"pascal","ada","cobol","fortran","perl"}; int i; char *t; t=names[3]; names[3]=names[4]; names[4]=t; for (i=0;i<=4;i++) printf("%s",names[i]); }

2 Answers  

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Write a prog to accept a given string in any order and flash error if any of the character is different. For example : If abc is the input then abc, bca, cba, cab bac are acceptable, but aac or bcd are unacceptable.

5 Answers   Amazon, Microsoft,

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3) Int Matrix of certain size was given, We had few valu= es in it like this. =97=97=97=97=97=97=97=97=97=97=97 1 = | 4 | | 5 | &= nbsp; | 45 =97=97=97=97=97=97=97=97=97=97=97 &n= bsp; | 3 | 3 | 5 | = | 4 =97=97=97=97=97=97=97=97=97=97=97 34 |&nbs= p; 3 | 3 | | 12 | &= nbsp; =97=97=97=97=97=97=97=97=97=97=97 3 | &nbs= p; | 3 | 4 | = | 3 =97=97=97=97=97=97=97=97=97=97=97 3 | = ; | | | = ; 3 | =97=97=97=97=97=97=97=97=97=97=97 &= nbsp; | | 4 | = ; | 4 | 3 We w= ere supposed to move back all the spaces in it at the end. Note: = If implemented this prog using recursion, would get higher preference.

0 Answers   RoboSoft,

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#define prod(a,b) a*b main() { int x=3,y=4; printf("%d",prod(x+2,y-1)); }

1 Answers  

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program to find magic aquare using array

4 Answers   HCL,

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1) int i=5; j=i++ + i++ + i++; printf("%d",j);This code gives the answer 15.But if we replace the value of the j then anser is different?why? 2)int i=5; printf("%d",i++ + i++ + i++); this givs 18.

8 Answers   IBPS, Infosys, TCS,

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Question: We would like to design and implement a programming solution to the reader-writer problem using semaphores in C language under UNIX. We assume that we have three readers and two writers processes that would run concurrently. A writer is to update (write) into one memory location (let’s say a variable of type integer named temp initialized to 0). In the other hand, a reader is to read the content of temp and display its content on the screen in a formatted output. One writer can access the shared data exclusively without the presence of other writer or any reader, whereas, a reader may access the shared memory for reading with the presence of other readers (but not writers).

1 Answers  

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main() { unsigned char i=0; for(;i>=0;i++) ; printf("%d\n",i); }

1 Answers  

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write a c program to print magic square of order n when n>3 and n is odd?

1 Answers   HCL,

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char *someFun() { char *temp = “string constant"; return temp; } int main() { puts(someFun()); }

1 Answers  

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