can u give me the c codings for converting a string into
the hexa decimal form......
Answer / ravi jaiswal
#include<stdio.h>
#include<conio.h>
#include<string.h>
void main()
{
char x[25];
int i=0;
printf("Enter a string");
gets(x);
while(x[i]!='\0')
{
printf("%x\t",x[i]);
i++;
}
getch();
}
| Is This Answer Correct ? | 3 Yes | 0 No |
main() { int i =0;j=0; if(i && j++) printf("%d..%d",i++,j); printf("%d..%d,i,j); }
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#define prod(a,b) a*b main() { int x=3,y=4; printf("%d",prod(x+2,y-1)); }
main() { static int var = 5; printf("%d ",var--); if(var) main(); }
#include<stdio.h> #include<conio.h> void main() { int a=(1,2,3,(1,2,3,4); switch(a) { printf("ans:"); case 1: printf("1");break; case 2: printf("2");break; case 3: printf("1");break; case 4: printf("4");break; printf("end"); } getch(); }
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