Answer / raghuram.a

#include <stdio.h>
#include<conio.h>
void putlong(unsigned long x)
{
if (x>=10)
{
putlong(x/10);
}
putchar(x%10+48);
}
main()
{
unsigned long a;
clrscr();
printf("enter long integer:");
scanf("%ld",&a);
putlong(a);
getch();
return 0;

}

Answer / prateek caire

void print(unsigned n)
{
static c = 0;
if( n < 10)
{
putchar(n + 48);
return;
}
int m = n%10;
print(n/10);
if(++c%3 == 0) putchar(',');
putchar(48 + m);
}

Answer / suraj gupta

#include<stdio.h>
#include<string.h>
void printInt(unsigned long x){
int div=1;
if (x > 10){
div=x/10;
printInt(div);
}
//putchar(x % 10+'0');Both will work fine
putchar(x % 10+48);
}
int main(){
long int a;
printf(" Enter integer value : ");
scanf("%d",&a);
printf("\n");
printInt(a);
return 0;
}

Answer / sanjay

#include<stdio.h>
#include<conio.h>

int main()
{
unsigned long abc=234455787; int div1;
div1=print_int(abc);
getch();
}


int print_int(long val)
{ int div=1; char c;
if (val>=10)
{
div=print_int(val/10);
}
putchar(val%10+48);
return (1);
}

Answer / meibella

void putLong(unsigned int x, unsigned int *a, int *j)
{
unsigned int temp = x/10;
unsigned int remainder = x%10;
a[(*j)++] = remainder;
if (temp < 1)
return ;
else
putLong(temp,a,j);


}
int main()
{
unsigned int * a = new unsigned int[12] ;
int j =0;
putLong(1735648,a,&j);
for (int i = j-1; i>=0; i--)
{
putchar(a[i]+48);
}
return 0;
}

Answer / rakesh

void main()
{
unsigned long n;
int i;
void putlong(unsigned long);
cout<<"\nEnter the number::";
cin>>n;
putlong(n);
}

void putlong(unsigned long n)
{
if(n==0)
return;
print(n/10);
putchar((n%10) + 48);

}

Print an integer using only putchar. Try doing it without using extra storage.

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