Answer / susie

Answer :

0

Explanation:

After ‘ptr’ reaches the end of the string the value pointed
by ‘str’ is ‘\0’. So the value of ‘str’ is less than that of
‘least’. So the value of ‘least’ finally is 0.

main() { unsigned int i=10; while(i-->=0) printf("%u ",i); }

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#include<stdio.h> main() { char s[]={'a','b','c','\n','c','\0'}; char *p,*str,*str1; p=&s[3]; str=p; str1=s; printf("%d",++*p + ++*str1-32); }

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