9*9 1:4:8 ratio using how to calculate the material for 40mm aggregate ,cement

Categories >> Engineering >> Civil Engineering
Suggest New Category

9*9 1:4:8 ratio using how to calculate the material for
40mm aggregate ,cement &sand please tell me answer

Question Posted / nagarajan

5 Answers
39198 Views
I also Faced
E-Mail Answers

Answers were Sorted based on User's Feedback

9*9 1:4:8 ratio using how to calculate the material for 40mm aggregate ,cement &sand please te..

Answer / ronak shah

first of all i m not understand 9*9.
so i consider 1m3
52% more shrinkage and wastage.
1.52m3
cement= 1.52/(1+4+8)=0.1169/(cement bag volume in m3)=
0.1169/0.0348= 3.35 bags so 168 kg/m3.

sand=1.52/(1+4+8)=0.1169*4=0.47m3

aggregate=1.52/(1+4+8)=0.1169*8=0.94m3

Is This Answer Correct ?

47 Yes

5 No

9*9 1:4:8 ratio using how to calculate the material for 40mm aggregate ,cement &sand please te..

Answer / sravan875

Cement =182.3 Kgs

Fine aggregate =182.3*4=729.2Kgs

COarse aggregate=182.3*8=1458.4Kgs

Is This Answer Correct ?

11 Yes

3 No

9*9 1:4:8 ratio using how to calculate the material for 40mm aggregate ,cement &sand please te..

Answer / sanjeev kumar singh

Dear sir
1cum cement concrete me material quantity
.9 cum.aggregate
.45 cum. Sand
.12 cum. Cement
Right answer kya hai

Is This Answer Correct ?

2 Yes

3 No

9*9 1:4:8 ratio using how to calculate the material for 40mm aggregate ,cement &sand please te..

Answer / sravan875

As per ratio 1:4:8
1=cement
4=fine aggregate
8=Coarse

Cement=182.3 Kgs

Fine aggregate =0.3076924*1750=538.46 Kgs

Coarse Aggregate =0.6153848*1950=1200 Kgs

Is This Answer Correct ?

3 Yes

9 No

9*9 1:4:8 ratio using how to calculate the material for 40mm aggregate ,cement &sand please te..

Answer / sravan875

1:4:8 Ratio means 1%cement,4%aggregate,8%sand.
cement percentage--1/13=0.0769231cum.
aggregate %---4*0.0769...=0.3076924cum.
Sand % ----8*0.0169...=0.6153848cum..

Cement=0.0769*2370kg/cum (unit weight of concrete)=182.30775kg

40mm Aggregate=(density 1950kg/cum).
aggregate needed=0.3076924*1950=600.00kg of aggregate

Sand density(dry,packed)---1600-1900kg/cum
sand(dry,packed)-0.6153848*1750=1076.9234 Kg of sand is required.

Cement=182.3 Kgs
Aggregate=600Kgs
Sand=1077 Kgs

Is This Answer Correct ?

3 Yes

18 No

Post New Answer

More Civil Engineering Interview Questions

Used Cement Mortar, Cement & Sand in 1 Square Meter or 1 Square Feet For 10-18mm Thick Plaster ? (1:6) (1:4)(1:3)

3 Answers IVRCL, L&T,

How to convert rainforcement calculation: Running meter to kg

23 Answers Interscape, Pratibha Industries,

how much quantity of cement bags are required to fill the one m3 of empty container.?

12 Answers L&T, NBDL, SEW Infrastructure,

In 120 m high RCC Chimney shell construction how we can calculate the inner and outer dia of shell at every +1 m level as this shell is inclined from bottom to top.

4 Answers

How to check slab shuttering level.? Or check list for slab ?

0 Answers

What is Leastcount of 1. Total station 2. Theodolite 3. Dumpy level 4. Plane Table

3 Answers

How will find compresive strenth of M20,M25,M30 after 7day,8day 28day etc please drive step by step not shot?

2 Answers

1)What's are the diff. types of column based on loading? 2)Is there any difference bitween Development length & Anchorage Length? 3) What is the basic diff. between one way & two way slab? 4) Where should use OPC & where should PPC?

3 Answers TPSC,

what is assumption consumption of steel per m3 for raft

2 Answers

Is 456 revised lastly in which year? & What are the revisions?

19 Answers L&T,

pls tell me , what is the water content

0 Answers

what is the length of a steel bar when it buy for the site????

4 Answers

For more Civil Engineering Interview Questions Click Here