Answer / sahil gupta

j k qpr qout s r
0 0 0 0 0 x
0 0 1 1 0 x
0 1 0 0 1 0 conversion table
0 1 1 0 1 0 by solve k -map qpr qnew s r j k t d
1 0 0 1 0 1 s=j(not q) 0 0 0 x 0 x 0 0
1 0 1 1 0 1 r=kq 0 1 1 0 1 x 1 1
1 1 0 1 x 0 1 0 0 1 x 1 1 0
1 1 1 0 x 0 1 1 x 0 x 0 0 1
x represents----->>"don't care"
then make k-map for S and R

Answer / raghu

by using 2 and gates and clk signal...

Answer / divya nair

first divide into two parts : the DESIRED part n the
PROCESSED part
the DESIRED part consist of J0,K0,Q0 n Q1
the PROCESSED part consist of S0 n R0
J0 K0 Q0 Q1 S0 R0
0 0 0 -------> 0 0 0
0 0 1 -------->1 0 0
0 1 0 -------->0 0 0
0 1 1 -------->0 0 1
1 0 0 -------->1 1 0
1 0 1 -------->1 0 0
1 1 0 -------->1 1 0
1 1 1 -------->0 0 1

THIS IS THE TRUTH TABLE FOR THE CONVERSION.
EXPLANATION AS FOLLOWS:
Q0=Q1=0,1 : NO TRANSITION STATE
Q0=0&Q1=1 : THE SET CONDITION,S0=1,R0=0
Q0=1&Q1=0 : THE RESET CONDITION,S0=0,R0=1

in NO TRANSITION STATE,the values of S0 n R0 equals 0

Answer / abhay srivastava

j k Qn Qn+1 s r
0 0 0 0 0 x
0 0 1 1 x 0
0 1 0 1 1 0
0 1 1 1 x 0
1 0 0 0 0 x
1 0 1 0 0 1
1 1 0 1 1 0
1 1 1 0 0 1



here x is don't care solve j k Qn

s=j.Qn
r=k.Qn(bar)

Answer / remila saraboth lousy

S=J.QBAR
R=K.Q


DATA INPUTS OUTPUTS INPUTS OUTPUTS
Q QBAR S R QN+1
J K
0 0 0 1 0 x 0
0 0 1 0 0 x 1
0 1 0 1 0 1 0
0 1 1 0 0 1 0
1 0 0 1 1 0 1
1 0 1 0 1 0 1
1 1 0 1 x 0 1
1 1 1 0 x 0 0

Answer / mike

s=Qn'k
r=QnJ

Answer / sathish

SIMPLE METHOD ,ONLY YOU KNOW FOR K-MAP

j k qpr qout s r
0 0 0 0 0 x
0 0 1 1 0 x
0 1 0 0 1 0 conversion table
0 1 1 0 1 0 qpr qnew s r j k t d
1 0 0 1 0 1 0 0 0 x 0 x 0 0
1 0 1 1 0 1 0 1 1 0 1 x 1 1
1 1 0 1 x 0 1 0 0 1 x 1 1 0
1 1 1 0 x 0 1 1 x 0 x 0 0 1
x represents don't care(0 OR 1)

Answer / saravanan

To convert SR ff to JK ff, the equation is S=(J*(~Q)) and
R=(K*(Q)). So by using these equation u can do the
connection now. Give the output of J&(Q bar) and give to S
input and the output of K&Q to R input.

Answer / bibha singh

j k q1 q2 s r
0 0 0 0 0 x
0 0 1 1 x 0
0 1 0 0 0 x
0 1 1 0 0 1
1 0 0 1 1 0
1 0 1 1 x 0
1 1 0 1 1 0
1 1 1 0 0 1

r=product of k and q1
s=product of j and compliment of q1

Answer / taposh chandra

q k y q(t+1)
0 0 0 0
0 0 1 0
0 1 0 1
0 1 1 1
1 0 0 1
1 0 1 0
1 1 0 1
1 1 1 0

Q=jy'+k'y

kindly,plesae tell me # the working of BTS # ITS CARDS SPECIFICATION # WORKING OF TRX,DUPLEXER,ASMA CARDS,FIFA # HOW WE ROUTE TRAFFICS # FLOW OF SMS,HOT CALLS,CALLS ETC

0 Answers  

X^2 - 4X - 2Y + Y^2 = 4 represents a circle with

4 Answers   BSNL,

What are the advantages of free wheeling diodes in a controlled in a controlled rectifier?

0 Answers  

in case of a bipolar junction transistor we are concerned with Vbe,,,Vce(in order to stabilise optiamally)but why don't we bother about Vbc?? why ?

3 Answers  

please send me rrb gorakhpur je teli question paper

0 Answers  

In the field of microprocessor what is DMA?why it is used?

13 Answers   Siemens,

Why we are using One End High ODU and One End Low ODU in Microwave Link?

1 Answers  

what is the significance of transistor number (exam. BC557,CIL188 etc) ?

0 Answers   ECL, VCV,

What are the commonly used filters?

0 Answers  

where we use zenor diode

3 Answers   HCL,

Explain what is a voltage transfer curve of an op-amp?

0 Answers  

What is the distance from an RF Transmitter that output power is determined?

0 Answers