Answer Posted / abhay srivastava

j k Qn Qn+1 s r
0 0 0 0 0 x
0 0 1 1 x 0
0 1 0 1 1 0
0 1 1 1 x 0
1 0 0 0 0 x
1 0 1 0 0 1
1 1 0 1 1 0
1 1 1 0 0 1



here x is don't care solve j k Qn

s=j.Qn
r=k.Qn(bar)

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