Answer / iamdon

The material of wire and the physical dimnsions are known.

1)From the physical property its resistivity(p)and melting
point can be found out(we need to depend upon techanical
specifications).

2)Resistance(R)of the wire can be calculated using the
relationship with the help of dimensional data
R=(p*l)/A where l=length of wire
A=cross sectional area of wire.
3)For a particular value of current(I)flowing through the
wire,the heat produced can be found by Joules law of
heating as
H=I*I*R.
4)Now we need to look into the ambient temperature in which
the wire is intended to work.After applying Newtons law of
cooling between allowable temperature of wire(considering
some factor of safety) and ambient temperature.We can find
current carrying capacity of wire.

Author:arbelectbit@yahoo.com

A group of machines (wind turbines) connected with 33KV feeder and each machines are having individual VCB. The 33KV feeder connected with 110KV/33KV substation. The 33KV feeder tripped by over current at Substation and fault recorded at Substation as OC-R&Y phase. Same time the group of machines VCB tripped by over voltage, the fault recorded voltage was above 66KV by numerical Under/Over voltage relay. While grid drop time, this much of voltage hike is possible?

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