char *someFun1()

{

char temp[ ] = “string";

return temp;

}

char *someFun2()

{

char temp[ ] = {‘s’, ‘t’,’r’,’i’,’n’,’g’};

return temp;

}

int main()

{

puts(someFun1());

puts(someFun2());

}

Answers were Sorted based on User's Feedback



char *someFun1() { char temp[ ] = “string"; return temp; } char *som..

Answer / susie

Answer :

Garbage values.

Explanation:

Both the functions suffer from the problem of dangling
pointers. In someFun1() temp is a character array and so the
space for it is allocated in heap and is initialized with
character string “string”. This is created dynamically as
the function is called, so is also deleted dynamically on
exiting the function so the string data is not available in
the calling function main() leading to print some garbage
values. The function someFun2() also suffers from the same
problem but the problem can be easily identified in this case.

Is This Answer Correct ?    11 Yes 0 No

char *someFun1() { char temp[ ] = “string"; return temp; } char *som..

Answer / rahulkulkarni

Variables are in function calls, hence on heap space. Variable address is being returned by function and when function returns the allocated space is freed.

Now accessing returned address will result in : segmentation fault.

As address no longer allocated to function, results in invalid address accessed by process.
As variable address does not exist ( hence variable address also , as heap is freed).

Is This Answer Correct ?    0 Yes 0 No

Post New Answer

More C Code Interview Questions

main() { int i=10; i=!i>14; Printf ("i=%d",i); }

1 Answers  


Declare an array of N pointers to functions returning pointers to functions returning pointers to characters?

1 Answers  


main() { int a[10]; printf("%d",*a+1-*a+3); }

1 Answers  


source code for delete data in array for c

1 Answers   TCS,


what is the code of the output of print the 10 fibonacci number series

2 Answers  






char *someFun() { char *temp = “string constant"; return temp; } int main() { puts(someFun()); }

1 Answers  


main() { int i = 0xff ; printf("\n%d", i<<2); } a. 4 b. 512 c. 1020 d. 1024

2 Answers   HCL,


Under linux environment can u please provide a c code for computing sum of series 1-2+3-4+5......n terms and -1+2-3+4-5...n terms..

2 Answers  


what will be the position of the file marker? a: fseek(ptr,0,SEEK_SET); b: fseek(ptr,0,SEEK_CUR);

2 Answers  


How we print the table of 3 using for loop in c programing?

7 Answers  


main() { int *ptr=(int*)malloc(sizeof(int)); *ptr=4; printf("%d",(*ptr)+++*ptr++); }

3 Answers   GNITC,


What is the output of the program given below main() { signed char i=0; for(;i>=0;i++) ; printf("%d\n",i); }

1 Answers  


Categories