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char *someFun1()
{
char temp[ ] = “string";
return temp;
}
char *someFun2()
{
char temp[ ] = {‘s’, ‘t’,’r’,’i’,’n’,’g’};
return temp;
}
int main()
{
puts(someFun1());
puts(someFun2());
}
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Answer Posted / susie
Answer :
Garbage values.
Explanation:
Both the functions suffer from the problem of dangling
pointers. In someFun1() temp is a character array and so the
space for it is allocated in heap and is initialized with
character string “string”. This is created dynamically as
the function is called, so is also deleted dynamically on
exiting the function so the string data is not available in
the calling function main() leading to print some garbage
values. The function someFun2() also suffers from the same
problem but the problem can be easily identified in this case.
| Is This Answer Correct ? | 11 Yes | 0 No |
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