main()
{
int i, n;
char *x = “girl”;
n = strlen(x);
*x = x[n];
for(i=0; i<n; ++i)
{
printf(“%s\n”,x);
x++;
}
}
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Answer / susie
Answer :
(blank space)
irl
rl
l
Explanation:
Here a string (a pointer to char) is initialized with a
value “girl”. The strlen function returns the length of the
string, thus n has a value 4. The next statement assigns
value at the nth location (‘\0’) to the first location. Now
the string becomes “\0irl” . Now the printf statement prints
the string after each iteration it increments it starting
position. Loop starts from 0 to 4. The first time x[0] =
‘\0’ hence it prints nothing and pointer value is
incremented. The second time it prints from x[1] i.e “irl”
and the third time it prints “rl” and the last time it
prints “l” and the loop terminates.
| Is This Answer Correct ? | 8 Yes | 3 No |
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C Code 
