main()

{

int i;

printf("%d",scanf("%d",&i)); // value 10 is given as
input here

}

Answers were Sorted based on User's Feedback



main() { int i; printf("%d",scanf("%d",&i)); // ..

Answer / susie

Answer :

1

Explanation:

Scanf returns number of items successfully read and not 1/0.
Here 10 is given as input which should have been scanned
successfully. So number of items read is 1.

Is This Answer Correct ?    24 Yes 1 No

main() { int i; printf("%d",scanf("%d",&i)); // ..

Answer / keerthi

1

Is This Answer Correct ?    1 Yes 2 No

Post New Answer

More C Code Interview Questions

main() { int i=-1,j=-1,k=0,l=2,m; m=i++&&j++&&k++||l++; printf("%d %d %d %d %d",i,j,k,l,m); }

1 Answers  


main() { int a=10,*j; void *k; j=k=&a; j++; k++; printf("\n %u %u ",j,k); }

1 Answers  


Predict the Output: int main() { int *p=(int *)2000; scanf("%d",2000); printf("%d",*p); return 0; } if input is 20 ,what will be print

2 Answers  


What is the hidden bug with the following statement? assert(val++ != 0);

1 Answers  


main() { char str1[] = {‘s’,’o’,’m’,’e’}; char str2[] = {‘s’,’o’,’m’,’e’,’\0’}; while (strcmp(str1,str2)) printf(“Strings are not equal\n”); }

1 Answers  


int DIM(int array[]) { return sizeof(array)/sizeof(int ); } main() { int arr[10]; printf(“The dimension of the array is %d”, DIM(arr)); }

2 Answers   CSC,


#include<conio.h> main() { int x,y=2,z,a; if(x=y%2) z=2; a=2; printf("%d %d ",z,x); }

1 Answers  


Can you send Code for Run Length Encoding Of BMP Image in C Language in linux(i.e Compression and Decompression) ?

0 Answers   Honeywell,


print a semicolon using Cprogram without using a semicolon any where in the C code in ur program!!

35 Answers   Tata Elxsi, TCS, VI eTrans,


Is there any difference between the two declarations, 1. int foo(int *arr[]) and 2. int foo(int *arr[2])

1 Answers  


#define square(x) x*x main() { int i; i = 64/square(4); printf("%d",i); }

4 Answers   Google, HCL, Quick Heal, WTF,


main( ) { void *vp; char ch = ‘g’, *cp = “goofy”; int j = 20; vp = &ch; printf(“%c”, *(char *)vp); vp = &j; printf(“%d”,*(int *)vp); vp = cp; printf(“%s”,(char *)vp + 3); }

1 Answers  


Categories