main()

{

char i=0;

for(;i>=0;i++) ;

printf("%d\n",i);

}

Answers were Sorted based on User's Feedback



main() { char i=0; for(;i>=0;i++) ; print..

Answer / mickey

-128

Is This Answer Correct ?    14 Yes 4 No

main() { char i=0; for(;i>=0;i++) ; print..

Answer / susie

Answer :

Behavior is implementation dependent.

Explanation:

The detail if the char is signed/unsigned by default
is implementation dependent. If the implementation treats
the char to be signed by default the program will print ā€“128
and terminate. On the other hand if it considers char to be
unsigned by default, it goes to infinite loop.

Rule:

You can write programs that have implementation
dependent behavior. But dont write programs that depend on
such behavior.

Is This Answer Correct ?    5 Yes 2 No

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