void main()
{
char a[]="12345\0";
int i=strlen(a);
printf("here in 3 %d\n",++i);
}
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Answer Posted / ravneet kaur
as this is a character array and would have string in double
quotes so this code shows an error i.e. *char wont changes
to *int.
| Is This Answer Correct ? | 0 Yes | 5 No |
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