Answer / susie

Answer :

“Strings are not equal”

“Strings are not equal”

….

Explanation:

If a string constant is initialized explicitly with
characters, ‘\0’ is not appended automatically to the
string. Since str1 doesn’t have null termination, it treats
whatever the values that are in the following positions as
part of the string until it randomly reaches a ‘\0’. So str1
and str2 are not the same, hence the result.

What is the subtle error in the following code segment? void fun(int n, int arr[]) { int *p=0; int i=0; while(i++<n) p = &arr[i]; *p = 0; }

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main() { char p[ ]="%d\n"; p[1] = 'c'; printf(p,65); }

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#include<stdio.h> #include<conio.h> void main() { int a=(1,2,3,(1,2,3,4); switch(a) { printf("ans:"); case 1: printf("1");break; case 2: printf("2");break; case 3: printf("1");break; case 4: printf("4");break; printf("end"); } getch(); }

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#include<stdio.h> main() { int a[2][2][2] = { {10,2,3,4}, {5,6,7,8} }; int *p,*q; p=&a[2][2][2]; *q=***a; printf("%d..%d",*p,*q); }

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PROG. TO PRODUCE 1 1 1 1 2 1 1 3 3 1 1 4 6 4 1

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abcdedcba abc cba ab ba a a

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Write a single line c expression to delete a,b,c from aabbcc

2 Answers   Microsoft,

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