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main()
{
char str1[] = {‘s’,’o’,’m’,’e’};
char str2[] = {‘s’,’o’,’m’,’e’,’\0’};
while (strcmp(str1,str2))
printf(“Strings are not equal\n”);
}
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Answer / susie
Answer :
“Strings are not equal”
“Strings are not equal”
….
Explanation:
If a string constant is initialized explicitly with
characters, ‘\0’ is not appended automatically to the
string. Since str1 doesn’t have null termination, it treats
whatever the values that are in the following positions as
part of the string until it randomly reaches a ‘\0’. So str1
and str2 are not the same, hence the result.
| Is This Answer Correct ? | 2 Yes | 1 No |
main() { int i; float *pf; pf = (float *)&i; *pf = 100.00; printf("\n %d", i); } a. Runtime error. b. 100 c. Some Integer not 100 d. None of the above
main() { extern int i; { int i=20; { const volatile unsigned i=30; printf("%d",i); } printf("%d",i); } printf("%d",i); } int i;
main() { int i=10; i=!i>14; Printf ("i=%d",i); }
Code for 1>"ascii to string" 2>"string to ascii"
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