Answer / susie

Answer :

4 1

Explanation:

The boolean expression needs to be evaluated only till the
truth value of the expression is not known. j is not equal
to zero itself means that the expression’s truth value is 1.
Because it is followed by || and true || (anything) => true
where (anything) will not be evaluated. So the remaining
expression is not evaluated and so the value of i remains
the same.

Similarly when && operator is involved in an expression,
when any of the operands become false, the whole
expression’s truth value becomes false and hence the
remaining expression will not be evaluated.

false && (anything) => false where (anything) will
not be evaluated.

main() { char *a = "Hello "; char *b = "World"; clrscr(); printf("%s", strcat(a,b)); } a. Hello b. Hello World c. HelloWorld d. None of the above

3 Answers   HCL,

---

There were 10 records stored in “somefile.dat” but the following program printed 11 names. What went wrong? void main() { struct student { char name[30], rollno[6]; }stud; FILE *fp = fopen(“somefile.dat”,”r”); while(!feof(fp)) { fread(&stud, sizeof(stud), 1 , fp); puts(stud.name); } }

1 Answers  

---

main() { int i =0;j=0; if(i && j++) printf("%d..%d",i++,j); printf("%d..%d,i,j); }

1 Answers  

---

Given an array of size N in which every number is between 1 and N, determine if there are any duplicates in it. You are allowed to destroy the array if you like.

21 Answers   ABC, eBay, Goldman Sachs, Google, HUP, Microsoft, TATA,

---

main() { { unsigned int bit=256; printf("%d", bit); } { unsigned int bit=512; printf("%d", bit); } } a. 256, 256 b. 512, 512 c. 256, 512 d. Compile error

1 Answers   HCL,

---

Is there any difference between the two declarations, 1. int foo(int *arr[]) and 2. int foo(int *arr[2])

1 Answers  

---

#ifdef something int some=0; #endif main() { int thing = 0; printf("%d %d\n", some ,thing); }

1 Answers  

---

main() { signed int bit=512, i=5; for(;i;i--) { printf("%d\n", bit >> (i - (i -1))); } } a. 512, 256, 0, 0, 0 b. 256, 256, 0, 0, 0 c. 512, 512, 512, 512, 512 d. 256, 256, 256, 256, 256

2 Answers   HCL,

---

#define SQR(x) x * x main() { printf("%d", 225/SQR(15)); } a. 1 b. 225 c. 15 d. none of the above

3 Answers   HCL,

---

main() { int c[ ]={2.8,3.4,4,6.7,5}; int j,*p=c,*q=c; for(j=0;j<5;j++) { printf(" %d ",*c); ++q; } for(j=0;j<5;j++){ printf(" %d ",*p); ++p; } }

1 Answers  

---

&#8206;#define good bad main() { int good=1; int bad=0; printf ("good is:%d",good); }

2 Answers  

---

main( ) { char *q; int j; for (j=0; j<3; j++) scanf(“%s” ,(q+j)); for (j=0; j<3; j++) printf(“%c” ,*(q+j)); for (j=0; j<3; j++) printf(“%s” ,(q+j)); }

1 Answers  

---