Answer / susie

Answer :

4 1

Explanation:

The boolean expression needs to be evaluated only till the
truth value of the expression is not known. j is not equal
to zero itself means that the expression’s truth value is 1.
Because it is followed by || and true || (anything) => true
where (anything) will not be evaluated. So the remaining
expression is not evaluated and so the value of i remains
the same.

Similarly when && operator is involved in an expression,
when any of the operands become false, the whole
expression’s truth value becomes false and hence the
remaining expression will not be evaluated.

false && (anything) => false where (anything) will
not be evaluated.

main() { if (!(1&&0)) { printf("OK I am done."); } else { printf("OK I am gone."); } } a. OK I am done b. OK I am gone c. compile error d. none of the above

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