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main()
{
int i=4,j=7;
j = j || i++ && printf("YOU CAN");
printf("%d %d", i, j);
}
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Answer / susie
Answer :
4 1
Explanation:
The boolean expression needs to be evaluated only till the
truth value of the expression is not known. j is not equal
to zero itself means that the expression’s truth value is 1.
Because it is followed by || and true || (anything) => true
where (anything) will not be evaluated. So the remaining
expression is not evaluated and so the value of i remains
the same.
Similarly when && operator is involved in an expression,
when any of the operands become false, the whole
expression’s truth value becomes false and hence the
remaining expression will not be evaluated.
false && (anything) => false where (anything) will
not be evaluated.
| Is This Answer Correct ? | 5 Yes | 0 No |
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C Code 
