Answer / susie

Answer :

Compiler Error

Explanation:

The structure yy is nested within structure xx.
Hence, the elements are of yy are to be accessed through the
instance of structure xx, which needs an instance of yy to
be known. If the instance is created after defining the
structure the compiler will not know about the instance
relative to xx. Hence for nested structure yy you have to
declare member.

main() { int i =10, j = 20; clrscr(); printf("%d, %d, ", j-- , --i); printf("%d, %d ", j++ , ++i); } a. 20, 10, 20, 10 b. 20, 9, 20, 10 c. 20, 9, 19, 10 d. 19, 9, 20, 10

4 Answers   HCL,

---

#include<stdio.h> main() { int i=1,j=2; switch(i) { case 1: printf("GOOD"); break; case j: printf("BAD"); break; } }

1 Answers  

---

main() { int i=4,j=7; j = j || i++ && printf("YOU CAN"); printf("%d %d", i, j); }

1 Answers  

---

#define DIM( array, type) sizeof(array)/sizeof(type) main() { int arr[10]; printf(“The dimension of the array is %d”, DIM(arr, int)); }

1 Answers  

---

#include<stdio.h> main() { int a[2][2][2] = { {10,2,3,4}, {5,6,7,8} }; int *p,*q; p=&a[2][2][2]; *q=***a; printf("%d----%d",*p,*q); }

1 Answers  

---

How will you print % character? a. printf(“\%”) b. printf(“\\%”) c. printf(“%%”) d. printf(“\%%”)

4 Answers   HCL,

---

main() { clrscr(); } clrscr();

2 Answers  

---

Given an array of characters which form a sentence of words, give an efficient algorithm to reverse the order of the words (not characters) in it.

2 Answers   Wipro,

---

#include<stdio.h> main() { int a[2][2][2] = { {10,2,3,4}, {5,6,7,8} }; int *p,*q; p=&a[2][2][2]; *q=***a; printf("%d..%d",*p,*q); }

1 Answers  

---

1. const char *a; 2. char* const a; 3. char const *a; -Differentiate the above declarations.

3 Answers  

---

# include <stdio.h> int one_d[]={1,2,3}; main() { int *ptr; ptr=one_d; ptr+=3; printf("%d",*ptr); }

1 Answers  

---

main() { int i=3; switch(i) { default:printf("zero"); case 1: printf("one"); break; case 2:printf("two"); break; case 3: printf("three"); break; } }

1 Answers  

---