#include<stdio.h>
main()
{
struct xx
{
int x;
struct yy
{
char s;
struct xx *p;
};
struct yy *q;
};
}
- 2 Answers
- 11318 Views
- I also Faced
- E-Mail Answers
Answers were Sorted based on User's Feedback
Answer / susie
Answer :
Compiler Error
Explanation:
in the end of nested structure yy a member have to be
declared.
| Is This Answer Correct ? | 8 Yes | 0 No |
Answer / dayana benny
The structure yy is nested within structure xx. Hence, the elements are of yy are to be accessed through the instance of structure xx, which needs an instance of yy to be known. If the instance is created after defining the structure the compiler will not know about the instance relative to xx. Hence for nested structure yy you have to declare member.
| Is This Answer Correct ? | 3 Yes | 0 No |
void main() { int i=5; printf("%d",i++ + ++i); }
int aaa() {printf(“Hi”);} int bbb(){printf(“hello”);} iny ccc(){printf(“bye”);} main() { int ( * ptr[3]) (); ptr[0] = aaa; ptr[1] = bbb; ptr[2] =ccc; ptr[2](); }
What is the difference between proc means and proc tabulate ? explain with a simple example when you have to use means or tabulate?
All the combinations of prime numbers whose sum gives 32
#if something == 0 int some=0; #endif main() { int thing = 0; printf("%d %d\n", some ,thing); }
main() { char *p = "hello world"; p[0] = 'H'; printf("%s", p); } a. Runtime error. b. “Hello world” c. Compile error d. “hello world”
Link list in reverse order.
Question: We would like to design and implement a programming solution to the reader-writer problem using semaphores in C language under UNIX. We assume that we have three readers and two writers processes that would run concurrently. A writer is to update (write) into one memory location (let’s say a variable of type integer named temp initialized to 0). In the other hand, a reader is to read the content of temp and display its content on the screen in a formatted output. One writer can access the shared data exclusively without the presence of other writer or any reader, whereas, a reader may access the shared memory for reading with the presence of other readers (but not writers).
find A^B using Recursive function
main() { register int a=2; printf("Address of a = %d",&a); printf("Value of a = %d",a); }
void main() { char a[]="12345\0"; int i=strlen(a); printf("here in 3 %d\n",++i); }
To Write a C program to remove the repeated characters in the entered expression or in entered characters(i.e) removing duplicates. String contains only lowercase characters ['a'-'z']
C Code 
