Answer / yash

while ((*target++ = *source++));

Answer / lavanya

for(i=0;(str2[i]=str1[i])!='\0';i++);

Answer / raghuram.a

while(str1[i]!=0) str2[j++]=str1[i++];

Answer / marrthand

for(i=0;i<=strlen(s1[i];i++){s1[i]=s2[i];}

Answer / gowrishankaran

while(str1[i]!=0) str2[j++]=str1[i++];

Answer / shruthirap

for(i=0; str2[i] = str1[i]; i++);

Answer / jitendra

void cpy_user(char *s, char *t)
{
while ((*s++ = *t++) != '\0');
}

Answer / anurag

SORRY !!!
The last posted Ans. is for reverse of the string in one
line...by mistake it has been posted in this.

Answer / anurag

int i=0,len=strlen(str);
int j=len/2;len--;
while(i<j)
{
*(str+i)^=*(str+len)^=*(str+i)^=*(str+len);
len--;i++;
}

Answer / vijay

strpy(n1,n2)
here copy of string n2 in string n1

int i=10; main() { extern int i; { int i=20; { const volatile unsigned i=30; printf("%d",i); } printf("%d",i); } printf("%d",i); }

1 Answers  

In a gymnastic competition, scoring is based on the average of all scores given by the judges excluding the maximum and minimum scores. Let the user input the number of judges, after that, input the scores from the judges. Output the average score. Note: In case, more than two judges give the same score and it happens that score is the maximum or minimum then just eliminate two scores. For example, if the number of judges is 5 and all of them give 10 points each. Then the maximum and minimum score is 10. So the computation would be 10+10+10, this time. The output should be 10 because 30/3 is 10.

0 Answers   TCS,

main() { int i=0; for(;i++;printf("%d",i)) ; printf("%d",i); }

1 Answers   Zoho,

main() { char *p = “ayqm”; printf(“%c”,++*(p++)); }

29 Answers   IBM, TCS, UGC NET, Wipro,

main() { int i=5; printf(“%d”,i=++i ==6); }

1 Answers  

void main() { int i=5; printf("%d",i++ + ++i); }

3 Answers  

main() { char *p; printf("%d %d ",sizeof(*p),sizeof(p)); }

6 Answers  

How to count a sum, when the numbers are read from stdin and stored into a structure?

1 Answers  

main() { int i =10, j = 20; clrscr(); printf("%d, %d, ", j-- , --i); printf("%d, %d ", j++ , ++i); } a. 20, 10, 20, 10 b. 20, 9, 20, 10 c. 20, 9, 19, 10 d. 19, 9, 20, 10

4 Answers   HCL,

main() { int (*functable[2])(char *format, ...) ={printf, scanf}; int i = 100; (*functable[0])("%d", i); (*functable[1])("%d", i); (*functable[1])("%d", i); (*functable[0])("%d", &i); } a. 100, Runtime error. b. 100, Random number, Random number, Random number. c. Compile error d. 100, Random number

1 Answers   HCL, rsystems,

Is this code legal? int *ptr; ptr = (int *) 0x400;

1 Answers  

How do you create a really large matrix (i.e. 3500x3500) in C without having the program crash? I can only reach up to 2500. It must have something to do with lack of memory. Please help!

1 Answers