Answer / deepjot kaur

void AddTwoNumbers();
#pragma startup AddTwoNumbers

void main()
{
printf("\n Executing Main...");
}


void AddTwoNumbers()
{
int num1,num2 = 0;
printf( "\nEnter number 1 : ");
scanf( "%d", &num1 );

printf( "\nEnter number 2 : ");
scanf( "%d", &num2 );

printf( "\nThe sum is = %d..." ,(num1 + num2) );
}

Answer / boss

Answer#1 above by Deepjot Kaur is the ONLY CORRECT ANSWER
Here. Pls ignore all others. They Posters did not understood
the Question basically.

The Qn is: We need to write a program in which there is one
main and a function. When executed, Function should run
first and then the Main().

Answer / sheenu

#include<stdio.h>
#include<conio.h>
void main()
{
int a,b,c;
clrscr();
printf("enter the value");
scanf("%d%d",&a,&b);
c=a+b;
printf("%d",c);
getch();
}

Answer / govind verma

but #prgma does not support on gcc... so this code is run only turbo c ......

Answer / naveen

#include <stdio.h>
#include <conio.h>
void main();
{

int a,b,c;
scanf("%d%d", &a,&b);
printf("enter a two numbers \n");
c=a+b;
printf("The add of two numbers are %d ",c);
clrscr();
getch();
}

Answer / salini

#include<stdio.h>
void main()
{
int a,b,c;
printf("Enter the first number :");
scanf("%d \n",&a);
printf("Enter the second number :");
scanf("%d \n",&b);
c=a+b;
printf("The addition of %d and %d is %d",&a,&b,&c);
}

Answer / pavan mustyala

#include <stdio.h>

int func()
{
int a = 10;
int b = 20;
printf("\nExecuting func FIRST...\n");

printf("Sum of the two numbers is %d", (a + b));
return (a + b);
}

int x = func();

int main(int argc, char* argv[])
{
printf("\nExecuting Main LAST...\n");
return 0;
}

Answer / nirmal bhattarai

#include<stdio.h>
#include<conio.h>
void main()
{
rintf("\n Executing Main...");
}


void AddTwoNumbers()
{
int num1,num2 = 0;
printf( "\nEnter number 1 : ");
scanf( "%d", &num1 );

printf( "\nEnter number 2 : ");
scanf( "%d", &num2 );

printf( "\nThe sum is = %d..." ,(num1 + num2) );
}
get();
}

Answer / b.vinod

#include<stdio.h>
main()
{
int a,b,c;
printf("Enter the value a,b");
scanf("%d%d",&a,&b);
c=a+b;
printf("c value is%d",a);
}

Answer / divya prabhu

#include<stdio.h>
#include<conio.h>

void add()
{
int a,b,c;
printf("\n Enter the two numbers to be added:");
scanf("%d %d",&a,&b);
c=a+b;
printf("\n The addition of two entered numbers is: %
d",c);
}


void main()
{
clrscr();
add();
getch();
}

main() { int x=5; clrscr(); for(;x<= 0;x--) { printf("x=%d ", x--); } } a. 5, 3, 1 b. 5, 2, 1, c. 5, 3, 1, -1, 3 d. –3, -1, 1, 3, 5

2 Answers   HCL,

Which one is taking more time and why ? :/home/amaresh/Testing# cat time.c //#include <stdio.h> #define EOF -1 int main() { register int c; while ((c = getchar()) != EOF) { putchar(c); } return 0; } ------------------- WIth stdio.h:- :/home/amaresh/Testing# time ./time_header hi hi hru? hru? real 0 m4.202s user 0 m0.000s sys 0 m0.004s ------------------ Witout stdio.h and with #define EOF -1 =================== /home/amaresh/Testing# time ./time_EOF hi hi hru? hru? real 0 m4.805s user 0 m0.004s sys 0 m0.004s -- From above two case , why 2nd case is taking more time ?

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