Answer / susie

Answer :

Compiler Error: Constant expression required in
function main.

Explanation:

The case statement can have only constant expressions (this
implies that we cannot use variable names directly so an error).

Note:

Enumerated types can be used in case statements.

main() { unsigned int i=65000; while(i++!=0); printf("%d",i); }

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main() { extern int i; { int i=20; { const volatile unsigned i=30; printf("%d",i); } printf("%d",i); } printf("%d",i); } int i;

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struct point { int x; int y; }; struct point origin,*pp; main() { pp=&origin; printf("origin is(%d%d)\n",(*pp).x,(*pp).y); printf("origin is (%d%d)\n",pp->x,pp->y); }

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what is brs test reply me email me kashifabbas514@gmail.com

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char *someFun() { char *temp = “string constant"; return temp; } int main() { puts(someFun()); }

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#include<stdio.h> int main() { int x=2,y; y=++x*x++*++x; printf("%d",y); } Output for this program is 64. can you explain how this output is come??

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How to reverse a String without using C functions ?

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main() { static int var = 5; printf("%d ",var--); if(var) main(); }

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write a program in c to merge two array

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Is the following code legal? struct a { int x; struct a b; }

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How can u say that a given point is in a triangle? 1. with the co-ordinates of the 3 vertices specified. 2. with only the co-ordinates of the top vertex given.

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#include<conio.h> main() { int x,y=2,z,a; if(x=y%2) z=2; a=2; printf("%d %d ",z,x); }

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