main()

{

extern int i;

i=20;

printf("%d",sizeof(i));

}

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main() { extern int i; i=20; printf("%d",sizeof(i))..

Answer / susie

Answer :

Linker error: undefined symbol '_i'.

Explanation:

extern declaration specifies that the variable i is defined
somewhere else. The compiler passes the external variable to
be resolved by the linker. So compiler doesn't find an
error. During linking the linker searches for the definition
of i. Since it is not found the linker flags an error.

Is This Answer Correct ?    22 Yes 4 No

main() { extern int i; i=20; printf("%d",sizeof(i))..

Answer / sahoo845

This program throws error in compilation. Because variable i is declared but not defined anywhere. Essentially, the variable isn’t allocated any memory. And the program is trying to change the value to 20 of a variable that doesn’t exist at all.

Is This Answer Correct ?    4 Yes 3 No

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