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main()
{
register int a=2;
printf("Address of a = %d",&a);
printf("Value of a = %d",a);
}
- 3 Answers
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Answer / susie
Answer :
Compier Error: '&' on register variable
Rule to Remember:
& (address of ) operator cannot be applied on register
variables.
| Is This Answer Correct ? | 3 Yes | 1 No |
Answer / chandra
It all depends on C/C++.
On C(GNU C/Visual studio C compiler), it will get a compiler
error.
since the keyword with register is stored in registers of
CPU rather than in memory locations of RAM.
On C++(GNU C++/Visual stdio C++ compiler), variable 'a' will
get an address of memory locations.
since register will automatically take address of memory
| Is This Answer Correct ? | 1 Yes | 0 No |
Answer / shrikantauti
Will produce an error as the memory address s not provided.
%u should had written instead of %d
| Is This Answer Correct ? | 0 Yes | 3 No |
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C Code 
