main()
{
register int a=2;
printf("Address of a = %d",&a);
printf("Value of a = %d",a);
}
Answers were Sorted based on User's Feedback
Answer / susie
Answer :
Compier Error: '&' on register variable
Rule to Remember:
& (address of ) operator cannot be applied on register
variables.
Is This Answer Correct ? | 3 Yes | 1 No |
Answer / chandra
It all depends on C/C++.
On C(GNU C/Visual studio C compiler), it will get a compiler
error.
since the keyword with register is stored in registers of
CPU rather than in memory locations of RAM.
On C++(GNU C++/Visual stdio C++ compiler), variable 'a' will
get an address of memory locations.
since register will automatically take address of memory
Is This Answer Correct ? | 1 Yes | 0 No |
Answer / shrikantauti
Will produce an error as the memory address s not provided.
%u should had written instead of %d
Is This Answer Correct ? | 0 Yes | 3 No |
Finding a number which was log of base 2
Can you send Code for Run Length Encoding Of BMP Image in C Language in linux(i.e Compression and Decompression) ?
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Given n nodes. Find the number of different structural binary trees that can be formed using the nodes.
16 Answers Aricent, Cisco, Directi, Qualcomm,
main() { char c; int i = 456; clrscr(); c = i; printf("%d", c); } a. 456 b. -456 c. random number d. none of the above
write a program to find out roots of quadratic equation "x=-b+-(b^2-4ac0^-1/2/2a"
main() { char a[4]="HELL"; printf("%s",a); }
1. const char *a; 2. char* const a; 3. char const *a; -Differentiate the above declarations.
main() { static int a[3][3]={1,2,3,4,5,6,7,8,9}; int i,j; static *p[]={a,a+1,a+2}; for(i=0;i<3;i++) { for(j=0;j<3;j++) printf("%d\t%d\t%d\t%d\n",*(*(p+i)+j), *(*(j+p)+i),*(*(i+p)+j),*(*(p+j)+i)); } }
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programming in c lanugaue programm will errror error with two header file one as stdio.h and other one is conio.h
Give a one-line C expression to test whether a number is a power of 2.