What the capacitor Current formula?, For 1 KVAr how amps
its required? for using the KVAr for boosting the PF Design
Calculation.( Eg: for 30 KVAr required how many KW?)
Answers were Sorted based on User's Feedback
Answer / sagar
Q = VIsin(fi)
capacitor current = I = Q/Vsin(fi)
For , 230 v and power factor angle 90 ,then
I = 1/230*sin 90 = 4.32 amp.
If power factor angle is 36.89 (power factor 0.8)
,then
P/Q = kw/KVAR = VIcos(fi)/VIsin(fi)
P/Q = cos(fi)/sin(fi) = Tan(fi)
P = Q tan(fi)
P = 30 tan(36.89) = 30 * 0.75 = 22.5 Kw
Is This Answer Correct ? | 3 Yes | 2 No |
Answer / kalanidhi
Current calculation for 200 kvar capacitor
CAPACITOR VOLTAGE CALCULATION
#System Voltage (MV) : 433V (WITH +- 5%)
#Voltage drop across (Maximum) : 433 x -5% = 21.65V
Capacitors working : 411.35 Volts.
CAPACITOR CURRENT CALCULATION
KVAR Calculation at 433 Volts.
KVAR 433 Volt (433)2
= ------------ 200KVAR
(411.35)2
187489
= ----------- 200 KVAR
169208
= 1.1 x 200 KVAR = 221.59
= 221.59 KVAR
Current for 221.56 KVAR at 433 V = 221.59
------------------------ x 1000
433 x 1.732 x 0.6
= 492 Amps.
Is This Answer Correct ? | 1 Yes | 0 No |
Answer / mohammad rafique
dear,sir
my answer is 1 kvar = 1.3122 will be
my 2nd answer is 30 kvar= 44.5 kw will be and the mantioned
by powr factor like this,current cos(f1)and (requred cos(f2)
if my answer is correct then i shall be obligged to you
Is This Answer Correct ? | 3 Yes | 3 No |
Answer / prasenjit chowdhury
Full load current 350 Amps, Line Voltage 430. 1 KVAR = How many Amps. What is the formula or calculation to sagest the capacitor seating on load.
Is This Answer Correct ? | 0 Yes | 0 No |
Answer / srinu
Kvar: 1.732* v*i
1kvar=1000var
I=1000/1.732*415 for three phas
I=1.392amps
Is This Answer Correct ? | 4 Yes | 5 No |
Answer / venkatesh o
normally Formula
Kvar= 1.732*V*I*Sin(pi)
If Pure Capacitor 90 Leads so The power factor is Unity(1)
Assume *V=415
*Sin(90)=1(But Reactive power is zero)
since I=Kvar/1.732*V*1 Eg. 1000/1.732*415*1=1.39A
other formula for Determine KW=KVAR/tan(pi)or KW=VIcos(PI)
Assume * cos(0.9)
since KW=KVAR/tan....Equ 1, take the cos invesr is equal to (0.9)=25.8419 ...Equ 2
KW=30KVAR/tan25.8419=61.94KW OR
they are more formulas
* KW=KVAR/tan(pi)
* Kw=KVA*cos(pi)
* Kw=SQroot(KVAZ^2-(KVAr)^2
Is This Answer Correct ? | 3 Yes | 5 No |
Answer / botsar joseph antony
Ic=IsinQ1-I'sinQ2
where Q1 = phi1 and Q2 = phi
I is the curent, before correction and I' is the current,
after correction.
Ic is the subject of formula.
Is This Answer Correct ? | 1 Yes | 7 No |
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