Answer Posted / sagar

Q = VIsin(fi)

capacitor current = I = Q/Vsin(fi)

For , 230 v and power factor angle 90 ,then

I = 1/230*sin 90 = 4.32 amp.

If power factor angle is 36.89 (power factor 0.8)
,then

P/Q = kw/KVAR = VIcos(fi)/VIsin(fi)

P/Q = cos(fi)/sin(fi) = Tan(fi)

P = Q tan(fi)

P = 30 tan(36.89) = 30 * 0.75 = 22.5 Kw

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