Answer / abo ibrahim

Active Power=1.732*Load Current*Line Voltage*P.F.
P.F=0.8.
Active Power= 30kw = 3o*1000= 30000w
Load Current= 30000\(1.732*440*0.8).
=49.21 Amp.

Answer / anand

Load Current= KW / 1.732 x Line Voltage x P.F
= 30000 / 1.732 x 440 x 0.7
= 56.28
= 56 A


Note:
Power factor of Inductive(Motor)load: 0.7

Answer / elangkumanan

1kw= 1000watt
power =1.732*440*I*0.80



KW*1000
= ----------------
1.732*440*I*0.80

30*1000
= -----------------
609.664


30000
= ------- 49.20A THAT IS ANSWER FOR THIS QUESTION
609.664

Answer / d v singh

30*1.35*746
--------------
1.732*440*.95*.85

30213
---------------
621.85

= 48.58 AMP

Answer / pinoy

P=1.732 X LINE VOLTGE X I ; NO NEED TO MULTIPLY BY P.F
SINCE POWER (KW) IS KNOWN HENCE,ONLY MULTIPLY BY P.F IF
P=KVA
I=30KW/1.732(440)
=39.37AMPERES,

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