consider a table which contain 4 columns,ename,eno,sal and
deptno, from this table i want to know ename who having
maximum salary in deptno 10 and 20.
Answers were Sorted based on User's Feedback
Answer / purushotham
select ename from table where sal in
(select max(sal) from table_name
where deptno in ('10','20')
group by deptno);
| Is This Answer Correct ? | 16 Yes | 8 No |
Answer / srilekha
select ename from table where sal=(select max(sal) from
table) and depetno in (10,20)
| Is This Answer Correct ? | 27 Yes | 20 No |
Answer / rohan
select empno from emp where (sal,deptno) in ( select max
(sal),deptno from emp where deptno in (10,20) group by
deptno)
| Is This Answer Correct ? | 13 Yes | 6 No |
Answer / rashmi_raju
SELECT ename FROM emp WHERE sal =(SELECT MAX(sal) FROM emp
WHERE deptno=10)
UNION
(SELECT ename FROM emp WHERE sal =(SELECT MAX(sal) FROM emp
WHERE deptno=20))
| Is This Answer Correct ? | 6 Yes | 0 No |
Answer / guest
Select emp_name from emp where sal =(Select Max(sal) from
emp where deptno=10) and deptno=10 union
Select emp_name from emp where sal =(Select Max(sal) from
emp where deptno=20)and deptno=20
| Is This Answer Correct ? | 6 Yes | 1 No |
Answer / kishore
select * from em where sal in (select max(sal) from em
where dno in (10,20) group by dno) and dno in (10,20)
where em = table name
dno = department number
sal = salary
| Is This Answer Correct ? | 4 Yes | 3 No |
Answer / anil pednekar
select table1.ename from (select deptno, max(sal) as sal1
from table1 group by deptno having deptno in(1,2)) as T1,
table1 where T1.deptno=table1.deptno and
T1.sal1=table1.sal
| Is This Answer Correct ? | 1 Yes | 0 No |
Answer / ashim
select * from (select id,dept,sal,dense_rank() over
(partition by dept order by sal desc) p from a_tab1)
where p=1
....by using this program we can find out the nth salary of
different department jus give p=n
| Is This Answer Correct ? | 1 Yes | 0 No |
select last_name,salary from employees where (salary,department_id) in ( select max(salary),
department_id from employees where department_id in (10,20) group by
department_id)
/
Output
LAST_NAME SALARY
------------------------- ----------
Hartstein 13000
Whalen 4400
| Is This Answer Correct ? | 1 Yes | 0 No |
SELECT A.EMP_NAME, SUM(B.MAX_SALARY) AS MAX_SAL, B.EMP_DEPT_NO FROM EMP_DETAILS A,
(SELECT MAX(EMP_SAL) AS MAX_SALARY, EMP_DEPT_NO FROM EMP_DETAILS WHERE EMP_DEPT_NO IN (10,20)
GROUP BY EMP_DEPT_NO) B
WHERE
A.EMP_SAL = B.MAX_SALARY
AND A.EMP_DEPT_NO = B.EMP_DEPT_NO
GROUP BY A.EMP_NAME, B.EMP_DEPT_NO
| Is This Answer Correct ? | 0 Yes | 0 No |
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