How many test cases are necessary to cover all the possible
sequences of statements (paths) for the following program
fragment? Assume that the two conditions are independent of
each other : -
…………
if (Condition 1)
then statement 1
else statement 2
fi
if (Condition 2)
then statement 3
fi
…………
a. Test Cases
b. 3 Test Cases
c. 4 Test Cases
d. Not achievable
Plz. Explain in Detail...
Thank you.
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Answers were Sorted based on User's Feedback
Answer / paulo
Yo can prepare a set of input values to go trough both
conditions, that would be one test case.
You can prepare another set of values to take the false path
in condition1 (the only one that have statement when false)
i.e:
If x > y then X=1
fi
If f > v then F=1
fi
Test case 1 would be X = 3, Y = 2, F=3, V=2
Test case 2, would be x= 3, Y = 4, F=3, F=4
So the answer would be 2 test cases, and as far as i can
see, that would be the option A, that have a missed number
| Is This Answer Correct ? | 55 Yes | 17 No |
Answer / madhavi
we prepare 4 test cases for path coverage for this question.why becoz we have to find out number of possible ways for path coverage.
| Is This Answer Correct ? | 28 Yes | 4 No |
Answer / nithya
Path Coverage ensures covering of all the paths from start to end.
So the correct answer is 4 test cases.
| Is This Answer Correct ? | 12 Yes | 2 No |
Answer / jagadish
for path coverage we have to check all the paths its like
boolean expression, (true, true) is one path, (true, false)
is the second path, (false, true) is third path and both
false is the fourth path. so to cover 100% path coverage it
needs 4 test cases to achieve it. Please clarify if i am wrong.
| Is This Answer Correct ? | 22 Yes | 14 No |
Answer / anand
It is 4 test cases for the path coverage. The first condition has two path Statement 1 and Statement 2 (True and False). Same way the second condition also has two paths Statement 3 and nothing/null ( as there is no else for the second condition ) but it still is path (there is no statement but still there is a path compiler can take...)
| Is This Answer Correct ? | 5 Yes | 2 No |
Answer / mandokar
It requires only 2 test cases as in the question he
mentioned "path", if it was condition then the answer could
have been 4 as jagdish said.
| Is This Answer Correct ? | 5 Yes | 5 No |
Answer / sachin karla
actually in statement testing,what happens like,3 cases arise in the program and it proceeds as:
case 1:the '+' sign becomes a 'space'.
case 2:'%xx' becomes byte with hexadecimal value 'xx'.
case 3:other alphanumeric char map themselves.
So guys,think about it and make a proper testing over it..
| Is This Answer Correct ? | 1 Yes | 1 No |
Answer / hayk grigoryan
TC1 c1 true, c2 true, TC2 c1 true, c2 false, TC3 c1 false, c2 true
| Is This Answer Correct ? | 0 Yes | 0 No |
Answer / anwar sayed
If its dependent there would be 4 cases
and if it is dependent it would be 3 test cases
| Is This Answer Correct ? | 0 Yes | 3 No |
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