Scientist decided to do a study on the population growth of
rabbits. Inside a controlled environment, 1000 rabbits were
placed.
Six months later, there were 1000Z rabbits. At the beginning
of the 3rd year, there were roughly 2828Z rabbits, which was
4 times what the scientists placed in there at the beginning
of the 1st year.
If Z is a positive variable, how many rabbits would be there
at the beginning of the 11th year?
- 1 Answers
- 5288 Views
- I also Faced
- E-Mail Answers
Answer / guest
At the beginning of the 11th year, there would be 1,024,000
rabbits.
At the beginning, there were 1000 rabbits. Also, there were
4000 rabbits at the beginning of third year which is equal
to 2828Z. Thus, Z = 4000/2828 i.e. 1.414 (the square root of 2)
Note that 2828Z can be represented as 2000*Z*Z (Z=1.414),
which can be further simplified as 1000*Z*Z*Z*Z
Also, it is given that at the end of 6 months, there were
1000Z rabbits.
It is clear that the population growth is 1.414 times every
six months i.e. 2 times every year. After N years, the
population would be 1000*(Z^(2N)) i.e. 1000*(2^N)
Thus, at the beginning of the 11th year (i.e. after 10
years), there would be 1000*(2^10) i.e. 1,024,000 rabbits.
| Is This Answer Correct ? | 4 Yes | 0 No |
in 10 hrs,if the cistern is filled ,then how much time the outlet takes to empty the cistern
You have only one container full of water. You didnt have any marker or measurement device. Find the half of the container.
how would u find d exact number of white maruti cars in mumbai???
15 Answers Bhel, Infosys, RR, TCS,
All of the students at a college are majoring in psychology, business, or both. 73% of the students are psychology majors, & 62% are business majors. If there are 200 students, how many of them are majoring in both psychology & business?
15 people--each has to pay Rs.20.. 20 people--each has to pay Rs.18.. for 40 people--how much has to pay
What is the minimum number of numbers needed to form every number from 1 to 7,000? Example: To form 4884, you would need 2 4s & 2 8s. 4822 requires a 4, a 8, & 2 2s, but you would not count the numbers again that you had already counted from making 4884.
A man has Ten Horses and nine stables as shown here. [] [] [] [] [] [] [] [] [] The man wants to fit Ten Horses into nine stables. How can he fit Ten horses into nine stables?
There is a shortage of tubelights, bulbs and fans in a village - Kharghar. It is found that ?All houses do not have either tubelight or bulb or fan. ?exactly 19% of houses do not have just one of these. ?atleast 67% of houses do not have tubelights. ?atleast 83% of houses do not have bulbs. ?atleast 73% of houses do not have fans. What percentage of houses do not have tubelight, bulb and fan?
there are 5 boxes each of which contains coins. all the boxes except one box contains coins whose weight is 100 grams.(each coin weight is 100gm). only one box contains coins tat weigh 90gm each. u r given a digital balance. in how many trys can u find out which box contains 90gm coins?
You have 8 coins. 3 of them weigh x units, 3 y units, 1 a units and 1 b units. They are all mixed and look identical. You have to find the lightest coin in minimum number of weighing (balance)
There are 25 horses and only five tracks in a race. How do you find the second coming horse of all the 25 horses, provided there is no stop clock? (obviously, a horse cannot participate more than once in a race).
28 Answers Amazon, Athena Health Care, Bloomberg, Citrix, Dreamz Group, Global Analytics, Juniper Networks, Microsoft, Oracle, Synopsis, UC Berkeley,
5+3+2=151012 9+2+4=183662 8+6+3=482466 5+4+5=202504 7+2+5=?
English 
