Answer / pavan_mustyala

1. Syntax Errors: Error found during compilation e.g.
missing semi colon, missing comma, undeclared identifier,
etc

2. Semantic Errors: Logical error in the program due to
which functionality behaves differently than expected.

3. Runtime Errors: Exceptions due to insufficient memory
and Segmentation fault, stack over flow, etc.

Answer / sivavendra

compilation errors(occurs during compilation) and runtime errors(occurs during runtime)...

Answer / vishwjeet singh

PROTOTYPE ERROR:when any header file is missing then we error hat was shown by compilling the program is prototype error.
SYNTEX ERROR: Actually these type of errors occured when
programmer misses the syntax.(Syntsx: (,),(.),(;),("") etc.)
Example:- printf("your sum is %d"c);
This may occure error "Syntax error".
Right Syntax is:printf("your sum is %d",c);

SYSTEMATIC ERROR:These type of errors occure when there is a
missmatch of functionallity.
Example: int sum is;
this may occure error because while declaring a variable c
is not allowed space( ).
Right Syntax is: int sum_is;

RUNTIME ERROR: Thes etype of errors also known as "linker
errors".These type of errors occure after compilation.This
will not give you the line where these type of errors occured.

Answer / sudhir seth

Syntax errors: Actually these type of errors occured when
programmer misses the syntax.(Syntsx: (,),(.),(;),("") etc.)
Example:- printf("your sum is %d"c);
This may occure error "Syntax error".
Right Syntax is:printf("your sum is %d",c);

Symmentic errors:These type of errors occure when there is a
missmatch of functionallity.
Example: int sum is;
this may occure error because while declaring a variable c
is not allowed space( ).
Right Syntax is: int sum_is;

Runtime errors: Thes etype of errors also known as "linker
errors".These type of errors occure after compilation.This
will not give you the line where these type of errors occured.

#include<iostream.h> #include<stdlib.h> static int n=0; class account { int age,accno; float amt; char name[20]; public: friend void accinfo(account [] ,int); void create(); void balenq(); void deposite(); void withdrawal(); void transaction(account []); }; void account :: create() { static int acc=1231; accno=acc+n; cout<<"\n\tENTER THE CUSTOMER NAME : "; cin>>name; cout<<"\n\t ENTER THE AGE : "; cin>>age; cout<<"\n\t ENTER THE AMOUNT : "; cin>>amt; // if(amt<=500) // cout<<"\n\tAMOUNT IS NOT SUFFICIENT TO CREATE AN ACCOUNT..."; cout<<"\n\t YOUR ACCOUNT NUMBER : "<<accno<<endl; n++; } void accinfo(account cus[],int ch) { int no,flag=0; cout<<"\n\t\tENTER YOUR ACCOUNT NUMBER : "; cin>>no; for(int i=0;i<=n&&flag==0;i++) if(no==cus[i].accno) { flag=1; switch(ch) { case 2: cus[i].balenq(); break; case 3: cus[i].deposite(); break; case 4: cus[i].withdrawal(); break; case 5: cus[i].transaction(cus); break; default: cout<<"\n\t\tEND OF THE OPERATION"; exit(1); } } if(flag==0) cout<<"\n\t\tYOUR ACCOUNT DOES NOT EXIST..."<<endl; } void account :: balenq() { cout<<"\n\t\tCUSTOMER NAME : "<< name << endl; cout<<"\n\t\tBALANCE : "<< amt << endl; } void account :: deposite() { int damt; cout<<"\n\t\tCUSTOMER NAME : "<< name <<endl; cout<<"\n\t\tBALANCE : "<< amt <<endl; cout<<"\n\tENTER THE AMOUNT TO BE DEPOSITED : "; cin>>damt; amt+=damt; cout<<"\n\t\tYOUR CURRENT BALANCE : "<<amt<<endl; } void account :: withdrawal() { int wamt; cout<<"\n\t\tCUSTOMER NAME : "<< name; cout<<"\n\t\tBALANCE : "<< amt; cout<<"\n\tENTER THE AMOUNT TO BE WITHDRAWN : "; cin>>wamt; if(amt-wamt>=500) { amt-=wamt; cout<<"\n\t\tYOUR CURRENT BALANCE : "<<amt; } else cout<<"\n\tYOUR BALANCE IS TOO LOW FOR WITHDRAWAL..."<<endl; } void account :: transaction (account cus[]) { int no,tamt,flag=0; cout<<"\n\tENTER THE RECEIVER'S ACCOUNT NUMBER : "; cin>>no; cout<<"\n\t\t ENTER THE AMOUNT : "; cin>>tamt; for(int i=0;i<=n&&flag==0;i++) if(cus[i].accno==no) { flag=1; cus[i].amt+=tamt; amt-=tamt; cout<<"\n\t\tYOUR CURRENT BALANCE : "<<amt<<endl; cout<<"\n\t\t RECEIVER'S BALANCE : "<<cus[i].amt<<endl; } if(flag==0) cout<<"\n\tRECEIVER'S ACCOUNT NUMBER IS NOT AVALIABLE..."<<endl; } void main() { account cus[10]; int ch; do { cout<<"\n\t\t BANK ACCOUNT"; cout<<"\n\t\t ************\n"; cout<<"\n\t\t1.CREATE AN ACCOUNT"; cout<<"\n\t\t2.BALANCE ENQUIRY"; cout<<"\n\t\t3.DEPOSITE"; cout<<"\n\t\t4.WITHDRAWAL"; cout<<"\n\t\t5.TRANSACTION"; cout<<"\n\t\t6.EXIT\n\n"; cout<<"\n\t\tENTER YOUR CHOICE : "; cin>>ch; if(ch==1) cus[n].create(); else accinfo(cus,ch); }while(1); }

1 Answers  

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how tally is useful?

2 Answers  

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write the value of x and y after execution of the statements: int x=19,y; y=x++ + ++x; x++; y++;

0 Answers  

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printy(a=3,a=2)

3 Answers  

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what is exceptions?

5 Answers   HCL, Wipro,

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class test { int a; public: test(int b):a(b){} void show(){ cout<<a; } }; void main() { test t1; test t2(5); t1.show(); t2.show(); } }

1 Answers  

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which typw of errors ? & how to solve it ?

0 Answers  

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Write a c-programe that input one number of four digits and find digits sum?

2 Answers  

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Assume that the int variables i and j have been declared, and that n has been declared and initialized. Write code that causes a "triangle" of asterisks of size n to be output to the screen. Specifically, n lines should be printed out, the first consisting of a single asterisk, the second consisting of two asterisks, the third consistings of three, etc. The last line should consist of n asterisks. Thus, for example, if n has value 3, the output of your code should be * ** *** You should not output any space characters. Hint: Use a for loop nested inside another for loop.

2 Answers   HCL,

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I'm having trouble with coming up with the correct code. Do I need to put a loop? Please let me know if I'm on the right track and what areas I need to correct. I still don't have a good grasp on this programming stuff. Thanks =) The assignment was to write a program using string functions that accepts a coded value of an item and displays its equivalent tag price. The base of the keys: 0 1 2 3 4 5 6 7 8 9 X C O M P U T E R S Sample I/O Dialogue: Enter coded value: TR.XX Tag Price : 68.00

3 Answers   UCB,

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Given an int variable n that has been initialized to a positive value and, in addition, int variables k and total that have already been declared, use a do...while loop to compute the sum of the cubes of the first n whole numbers, and store this value in total . Thus if n equals 4, your code should put 1*1*1 + 2*2*2 + 3*3*3 + 4*4*4 into total . Use no variables other than n , k , and total .

3 Answers  

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what is macro in c? Difference between single linked list & double linked list what is fifo & lifo? what is stack & queue?

2 Answers   TCS,

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