main()
{
printf("%x",-1<<4);
}
Answers were Sorted based on User's Feedback
Answer / susie
Answer :
fff0
Explanation :
-1 is internally represented as all 1's. When
left shifted four times the least significant 4 bits are
filled with 0's.The %x format specifier specifies that the
integer value be printed as a hexadecimal value.
| Is This Answer Correct ? | 120 Yes | 22 No |
Answer / sourab
thts ans is ture 4 16 bit compiler ,for 32 bit ans is fffffff0.
| Is This Answer Correct ? | 40 Yes | 9 No |
I need your help, i need a Turbo C code for this problem.. hope u'll help me guys.? Your program will have a 3x3 array. The user will input the sum of each row and each column. Then the user will input 3 values and store them anywhere, or any location or index, temporarily in the array. Your program will supply the remaining six (6) values and determine the exact location of each value in the array. Example: Input: Sum of row 1: 6 Sum of row 2: 15 Sum of row 3: 24 Sum of column 1: 12 Sum of column 2: 15 Sum of column 3: 18 Value 1: 3 Value 2: 5 Value 3: 6 Output: Sum of Row 1 2 3 6 4 5 6 15 7 8 9 24 Sum of Column 12 15 18 Note: Your program will not necessary sort the walues in the array Thanks..
#include<stdio.h> main() { struct xx { int x=3; char name[]="hello"; }; struct xx *s; printf("%d",s->x); printf("%s",s->name); }
What is the problem with the following code segment? while ((fgets(receiving array,50,file_ptr)) != EOF) ;
main() { if (!(1&&0)) { printf("OK I am done."); } else { printf("OK I am gone."); } } a. OK I am done b. OK I am gone c. compile error d. none of the above
Write a C program that defines a 2-dimentional integer array called A [50][50]. Then the elements of this array should randomly be initialized either to 1 or 0. The program should then print out all the elements in the diagonal (i.e. a[0][0], a[1][1],a[2][2], a[3][3], ……..a[49][49]). Finally, print out how many zeros and ones in the diagonal.
/*what is the output for*/ void main() { int r; printf("Naveen"); r=printf(); getch(); }
main() { int i =0;j=0; if(i && j++) printf("%d..%d",i++,j); printf("%d..%d,i,j); }
Predict the Output: int main() { int *p=(int *)2000; scanf("%d",2000); printf("%d",*p); return 0; } if input is 20 ,what will be print
main() { int i, j; scanf("%d %d"+scanf("%d %d", &i, &j)); printf("%d %d", i, j); } a. Runtime error. b. 0, 0 c. Compile error d. the first two values entered by the user
main() { char *cptr,c; void *vptr,v; c=10; v=0; cptr=&c; vptr=&v; printf("%c%v",c,v); }
Given an array of size N in which every number is between 1 and N, determine if there are any duplicates in it. You are allowed to destroy the array if you like.
21 Answers ABC, eBay, Goldman Sachs, Google, HUP, Microsoft, TATA,
#include<stdio.h> main() { char s[]={'a','b','c','\n','c','\0'}; char *p,*str,*str1; p=&s[3]; str=p; str1=s; printf("%d",++*p + ++*str1-32); }