Answer / wajahat hussain

pass English =80%
fail=100-80=20%
pass Math = 70%
fail in Math=100-70=30%
fail in both=10%
total fail students= fail in Eng+fail in Math-common
= 20+30-10=40%
if 40% fail then 60% will pass
let total students=x
hence
60% 0f (total students)=144
60/100 of (x)= 144
x=(144x100)/60
X=240
total students=240

Answer / kw

E: 80%, Fail in both: 10%, therefore only M pass is 10%
M: 70%, fail in both: 10%, therefore only E pass is 20%
100% = all fail + only E pass + only M pass + both E and M
pass
100%=10%+20%+10% + both E and M pass
Therefore, both E and M pass = 60%
60%=> 144
100% => 240
Answer: 240

Answer / vikram

240 appeared for the test

Answer / wajahat hussain

fail in English=100-80=20%
fail in Math =100-70=30%
fail in both=10%
total fail= fail in Eng+fail in Math-common
= 20+30-10
= 40%
if 40% failed than 60% passed
let total students=x
hence
60%of(x)=144
x=(144x100)/60
X=240
total number of students=240

Answer / abimozhi

In an examination, 60% passed in English and 70%in Maths,but 20% failed in both of these subjects.If 2500 candidates passed in both the subjects, the number of the candidates appeared for the examination?

Answer / ram

240 is the right answer
bcos

if u assume 160 as answer

160 -100%
144 - 90%
16 - 10%
if u say 90% passed in both and 10% failed in both
then whey they are asking
80% pass in english, 70%pass in maths in the question?
Think buddies

Answer / pradeep

240 appeared for the test

Answer / kamal kumar das

total pass % of candidates in both subjects= 80%+70%=150% . but given 10% failed in both so 90% passed in both. given 90%=144then 1%=144/90 and 150%=144/90*150=240

Answer / bhavna kuklani

can not find out.

Answer / rajesh

144 will passed in both ,so 144 willappear to the test.

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