Answer / jikku joseph

Total vol of the water is remain constant
since v r not adding or removing any water
and that is equal to (3.14/4)*D^2*H
This must be equal to the sum of new of new vol of water in
2 cylenders
ie (3.14/4)*D^2*H= (3.14/4)D^2*h+(3.14/4)d^2*h
by solving this v can get
h=(D^2*H)/(D^2+d^2)

Answer / arun

@shivaray...i dont think there is any relation b/w d and
H..so choosing the new volume with (H-h) is wrong...the
volume in the vessel wit 'd' as dia shud have only h and
not H-h...so the final ans is
h=D^2*H/(d^2+D^2)..

Answer / jodh

Hi Shivararay, Sorry to say that your answer is not exactly
right but your logic is very appereciating .........Height
after equablibrium in both the vessels will be equal
because of atmospheric pressure.So, height for dia. d is
not H-h.
I congratulate mr. Arun for his Correct answer i.e.
h= D2H/(D2 + d2)

Answer / siddaraju v

volume (Pi*D^2/4)*H=volume {(Pi*d^2/4)*h+(Pi*D^2/4)*h}

i.e.
h=H/{1+(d/D)^2}

Answer / akansha

Answer
# 2 is correct.
Don't consider other options..

Answer / abhinav patel

vol before connecting = vol after equlibrium
(3.14/4)*(D^2)*H = (3.14/4)*(D^2)*h +(3.14/4)*(d^2)*H
(3.14/4)*(D^2)*H = (3.14/4)h{(D^2)+(d^2)}
h={(D^2)/(D^2)+(d^2)}* H
pls sent me its correct or not

Answer / vishnu

@ jikku

ur answer is correct only if the two vessels are kept at
same level

Answer / sudip

If their base level is equal,then ans is "h" for both of them
else,
the volume of water decrease in "H" dia vessel=the volume occupied by that water in "h" dia vessel.
therefore the correct ans is
height=D^2*(H-h)/d^2

Answer / banke bihari

h=(D^2*H)/(D^2+d^2)
beacause after equlibrium is achieved, the height of water
in both the vessels must be same.
3.14h(D^2+d^2)/4=3.14D^2H/4..

Answer / deepak waje

sum of volumes of the water in both vessel will be equal
to the volume of water in vessel with dia D & filled up to
height H.
so as per equation,
D(H-h)=dh

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