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Suppose there are two vessels. One of diameter = D and
other vessel dia = d. Suppose in vessel with dia D, water
is filled upto height H and vessel with dia d is empty. Now
both vessels are connected.Water will flow from D dia vesel
to small d dia vessel.Suppose after equilibrium height of
water in vessel with dia D is h. How much is h in terms of
D, d,H etc?
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Answer Posted / jikku joseph
Total vol of the water is remain constant
since v r not adding or removing any water
and that is equal to (3.14/4)*D^2*H
This must be equal to the sum of new of new vol of water in
2 cylenders
ie (3.14/4)*D^2*H= (3.14/4)D^2*h+(3.14/4)d^2*h
by solving this v can get
h=(D^2*H)/(D^2+d^2)
| Is This Answer Correct ? | 50 Yes | 3 No |
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