Answer / siddhartha

@Monu, even if 9 stones are there, only two weighings are
required...
In general, in n weighings, you can determine the heavier
stone out of 3^n stones...
If 9 stones are there...
3---3---3
weigh the first two... if one is heavy, take that group,
else take the third group of three...
In this group of three thus taken, weigh any two. If any of
them if heavy, that is the stone.
Else the remaining one stone is the heavier one... :)

Answer / vijayaraj

monu ...you r wrong. There 8 stones. out of which one is
heavier.
2 times needed. divide 3,3,2 is correct.

Answer / debaroon

Urmila,Vamsee,Vishwa or any one can give the answer with
clear justification in details.

Answer / monu

idiots...........
read the question properly

is says that there are 8 stones with similar weight
EXCEPT 1 i.e. total 9 stones are there.....

now divide 4 on each side.That makes it 8
reamining 1 which is heavier then others...

so....minimum weight required on both the side is 4..

got it..........

Answer / kiru, chennai

minimum weighing needed 3,

Answer / shilpa

divide the stones into 4 and 4, weight it find which is
heavy. Consider which is high weighted and then again
divide those stones into 2 and 2, weight it find which is
hevy. consider which is high in weight and weigh the
remaining 2 weights and thus highest weighed is found. Thus
Answer is 3.

Answer / sanat

the right answer is 3

first divide the stones into 2parts 4 4
then see which one is heavier

then divide the heavier part into two parts 2 2

then measure the two stones of heavier part

Answer / dummi

7

Answer / kiru, chennai

minimum no of steps required:3
answer:
1 2 3 4 5 6 7 8
take 1,2&3,4
if both are equal move on to next
take 3,4&5,6
if both are equal move on next
take 6&7
if both are equal 8is the heavier one
else 7 is the heavier one
else
take 4 & 5
if both are equal
6 is the heavier on
else
5 is the heavier
else
take 2 & 5
if both are equal
1 is the heaveier one
else
2 is the heavier one

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