Answer / guest

65292

As per given conditions, there are three possible
combinations for 2nd, 3rd and 4th digits. They are (3, 0,
7) or (4, 1, 8) or (5, 2, 9)

It is given that there are 3 pairs whose sum is 11. All
possible pairs are (2, 9), (3, 8), (4, 7), (5, 6). Now
required number is 5 digit number and it contains 3 pairs
of 11. So it must not be having 0 and 1 in it. Hence, the
only possible combination for 2nd, 3rd and 4th digits is
(5, 2, 9)

Also, 1st digit is thrice the last digit. The possible
combinations are (3, 1), (6, 2) and (9, 3), out of which
only (6, 2) with (5, 2, 9) gives 3 pairs of 11. Hence, the
answer is 65292.

Answer / niket

sum should b 11
so possible combinations are (2,9),(3,8),(4,7),(5,6)
that means 0 and 1 is not there.
let no is "abcde"
now given that,
d=b+4;
c=b-3;
hence d=c+7;
hence c must be 2
hence d=9;
hence b=5;
also a=3e is given
hence a=6 & e=2.
hence number is 65292

Answer / srinu

65292

Answer / aman majhi

There are 5 digit
According to questions 4 th digit is greater than 2 digit and the 3 digit is 3 less than he 2 digit .
Assuming 2 digit from 0 to 9
We get the only possible numbers are
(4,1,8) and (529).
Now the 1 digit is thrice the 5 digit, that means if 1 digit is (3y) then the 5 digit is (y).
Assuming the possible numbers for y from 0 to 9 , we get the safe number as
(3,4,1,8,1)
(6,4,1,8,2)
(9,4,1,8,3)
(3,5,2,9,1)
(6,5,2,9,2)
(9,5,2,9,2)
Now there are three pair whose sum are 11 . The only possible set is (6,5,2,9,2).
Therefore the safe number is (6,5,2,9,2).

Answer / rohit

Ans: 64182

All conditions will be satified with this key.

Answer / guest

answer is 24186
here all conditions are saticified
and observe there are 3 pairs
i,e.(2,8,1)(1,4,6)(

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