Given 1 to n distinct random number of which n+1th element
was duplicated. How do find the duplicate element and
explain the time complexity of the algorithm.
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An array of size 5X5 is given to us. The elements from 1 to 25 are to be inserted in the array, such that starting from a particular position for an element i, the next element i+1can be inserted only at the mentioned positions (u,v), and if these all positions are occupied then it returns giving a count of how many positions have been occupied in the array: (u,v) = (x+/-3 , y) (u,v) = (x , y+/-3) (u,v) = (x+/-2 , y+/-2). Example: if the starting element is 1 with the given positions (1,2), then next element 2 can be placed at any one of the positions marked with *. _ _ _ _ _ 1 _ _ _ * _ _ _ _ _ _ _ * _ _ * _ _ _ _
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