void main()
{
int i,j=2;
for(i=0;i<3;i++)
if(j=i)
cout<<"Lotus ";
else
cout<<"Rose ";
}
Its result is Rose Lotus Lotus.. How? Explain it?
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Answer / nc
In the assignment operations...if the assigned value is 0
then it denotes false and for any other number 1,2,3...it
denotes true.So for i=0 i.e j becomes 0 means condition
becomes false so it displays Rose and for rest of the values
of i it displays Lotus.
| Is This Answer Correct ? | 10 Yes | 0 No |
Answer / pasha nitw
i think u confused at step 5
if(j=i) is different from if(j==i)
where as in if(j=i)
first i value assigned to j value for entire loop
then it cheks the expression.
according to this
if(0)
if(1)
if(2)
.
.
.
.
| Is This Answer Correct ? | 6 Yes | 2 No |
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