Answer / susie

Answer :

10 9 8 7 6 5 4 3 2 1 0 65535 65534…..

Explanation:

Since i is an unsigned integer it can never become negative.
So the expression i-- >=0 will always be true, leading to
an infinite loop.

Answer / renu

9 8 7 6 5 4 3 2 1 0 424 4235

main() { float me = 1.1; double you = 1.1; if(me==you) printf("I love U"); else printf("I hate U"); }

1 Answers  

---

main() { char *p; int *q; long *r; p=q=r=0; p++; q++; r++; printf("%p...%p...%p",p,q,r); }

1 Answers  

---

#define SQR(x) x * x main() { printf("%d", 225/SQR(15)); } a. 1 b. 225 c. 15 d. none of the above

3 Answers   HCL,

---

what is oop?

3 Answers  

---

Write a complete program that consists of a function that can receive two numbers from a user (M and N) as a parameter. Then print all the numbers between the two numbers including the number itself. If the value of M is smaller than N, print the numbers in ascending flow. If the value of M is bigger than N, print the numbers in descending flow. may i know how the coding look like?

2 Answers  

---

main() { int x=5; clrscr(); for(;x<= 0;x--) { printf("x=%d ", x--); } } a. 5, 3, 1 b. 5, 2, 1, c. 5, 3, 1, -1, 3 d. –3, -1, 1, 3, 5

2 Answers   HCL,

---

main() { unsigned int i=10; while(i-->=0) printf("%u ",i); }

2 Answers   HP,

---

How to swap two variables, without using third variable ?

104 Answers   AB, ADP, BirlaSoft, Cisco, Cygnet Infotech, HCL, Hewitt, Honeywell, HP, IBM, Infosys, Manhattan, Microsoft, Mobius, Percept, Satyam, SofTMware, TCS, Wipro, Yamaha,

---

struct point { int x; int y; }; struct point origin,*pp; main() { pp=&origin; printf("origin is(%d%d)\n",(*pp).x,(*pp).y); printf("origin is (%d%d)\n",pp->x,pp->y); }

1 Answers  

---

write a origram swaoing valu without 3rd variable

2 Answers  

---

Write a C program that defines a 2-dimentional integer array called A [50][50]. Then the elements of this array should randomly be initialized either to 1 or 0. The program should then print out all the elements in the diagonal (i.e. a[0][0], a[1][1],a[2][2], a[3][3], ……..a[49][49]). Finally, print out how many zeros and ones in the diagonal.

2 Answers  

---

#include<stdio.h> main() { char s[]={'a','b','c','\n','c','\0'}; char *p,*str,*str1; p=&s[3]; str=p; str1=s; printf("%d",++*p + ++*str1-32); }

2 Answers   CNSI,

---