Answer / susie

Answer :

10 9 8 7 6 5 4 3 2 1 0 65535 65534…..

Explanation:

Since i is an unsigned integer it can never become negative.
So the expression i-- >=0 will always be true, leading to
an infinite loop.

Answer / renu

9 8 7 6 5 4 3 2 1 0 424 4235

main() { int i; float *pf; pf = (float *)&i; *pf = 100.00; printf("\n %d", i); } a. Runtime error. b. 100 c. Some Integer not 100 d. None of the above

2 Answers   HCL, LG,

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#include<stdio.h> main() { char s[]={'a','b','c','\n','c','\0'}; char *p,*str,*str1; p=&s[3]; str=p; str1=s; printf("%d",++*p + ++*str1-32); }

1 Answers  

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Write a C program to print ‘Campus Force training’ without using even a single semicolon in the program.

3 Answers   Wipro,

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main() { int a=2,*f1,*f2; f1=f2=&a; *f2+=*f2+=a+=2.5; printf("\n%d %d %d",a,*f1,*f2); }

6 Answers  

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main ( ) { static char *s[ ] = {“black”, “white”, “yellow”, “violet”}; char **ptr[ ] = {s+3, s+2, s+1, s}, ***p; p = ptr; **++p; printf(“%s”,*--*++p + 3); }

1 Answers  

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What is the hidden bug with the following statement? assert(val++ != 0);

1 Answers  

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Is the following code legal? struct a { int x; struct a *b; }

2 Answers  

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What is the output of the program given below main() { signed char i=0; for(;i>=0;i++) ; printf("%d\n",i); }

1 Answers  

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struct Foo { char *pName; char *pAddress; }; main() { struct Foo *obj = malloc(sizeof(struct Foo)); clrscr(); obj->pName = malloc(100); obj->pAddress = malloc(100); strcpy(obj->pName,"Your Name"); strcpy(obj->pAddress, "Your Address"); free(obj); printf("%s", obj->pName); printf("%s", obj->pAddress); } a. Your Name, Your Address b. Your Address, Your Address c. Your Name Your Name d. None of the above

2 Answers   HCL,

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main() { char *p = “ayqm”; printf(“%c”,++*(p++)); }

29 Answers   IBM, TCS, UGC NET, Wipro,

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print a semicolon using Cprogram without using a semicolon any where in the C code in ur program!!

35 Answers   Tata Elxsi, TCS, VI eTrans,

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Is the following code legal? struct a { int x; struct a b; }

1 Answers  

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