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print a semicolon using Cprogram without using a semicolon
any where in the C code in ur program!!
- 35 Answers
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Answer / anshu ranjan
#include<stdio.h>
void main()
{
if(printf("%c",59)){}
}
\\actually, this is correct
| Is This Answer Correct ? | 104 Yes | 3 No |
Answer / vinay_csjm
void main()
{
if(printf("semicolon")){}
if(printf(getch())){}
}
| Is This Answer Correct ? | 72 Yes | 35 No |
Answer / ankit popli
Answer#2 has a mistake thats why its not working in TURBO C/C++.....i.e
void main()
{
while(!printf("\nHello World"))
{}
}
| Is This Answer Correct ? | 3 Yes | 0 No |
Answer / arun chauhan
#include<stdio.h>
void main()
{
if(printf("semicolon"))
{}
}
when you compile and run the program it will not stop at the console. You can see the result with the help of Alt+F5
| Is This Answer Correct ? | 2 Yes | 0 No |
Answer / rakesh
#include<stdio.h>
void main()
{
if(printf("semicolon")){}
if(getch()){}
}
this will print the word 'semicolon'
| Is This Answer Correct ? | 3 Yes | 2 No |
main() { static int a[3][3]={1,2,3,4,5,6,7,8,9}; int i,j; static *p[]={a,a+1,a+2}; for(i=0;i<3;i++) { for(j=0;j<3;j++) printf("%d\t%d\t%d\t%d\n",*(*(p+i)+j), *(*(j+p)+i),*(*(i+p)+j),*(*(p+j)+i)); } }
void main() { int i=10, j=2; int *ip= &i, *jp = &j; int k = *ip/*jp; printf(“%d”,k); }
Give a one-line C expression to test whether a number is a power of 2.
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union u { union u { int i; int j; }a[10]; int b[10]; }u; main() { printf("\n%d", sizeof(u)); printf(" %d", sizeof(u.a)); // printf("%d", sizeof(u.a[4].i)); } a. 4, 4, 4 b. 40, 4, 4 c. 1, 100, 1 d. 40 400 4
Write out a function that prints out all the permutations of a string. For example, abc would give you abc, acb, bac, bca, cab, cba. You can assume that all the characters will be unique.
5 Answers IITR, Microsoft, Nike,
Finding a number multiplication of 8 with out using arithmetic operator
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25 Answers EA Electronic Arts, Google, Motorola,
main() { char name[10],s[12]; scanf(" \"%[^\"]\"",s); } How scanf will execute?
main() { char *cptr,c; void *vptr,v; c=10; v=0; cptr=&c; vptr=&v; printf("%c%v",c,v); }
main() { char *p="hai friends",*p1; p1=p; while(*p!='\0') ++*p++; printf("%s %s",p,p1); }
C Code 
