ENGINEERING ECONOMY - EXAMPLE 7.1 : In engineering economy, the future value of

ENGINEERING ECONOMY - EXAMPLE 7.1 : In engineering economy, the future value of first year is FV = PV (1 + i). For second year it is FV = PV (1 + i) (1 + i). For third year it is FV = PV (1 + i) (1 + i)(1 + i) where FV = future value, PV = present value, i = interest rate per period, n = the number of compounding periods. By induction, what is the future value of $1000 for 5 years at the interest rate of 6 %?

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ENGINEERING ECONOMY - EXAMPLE 7.1 : In engineering economy, the future value of first year is FV = P..

Answer / kangchuentat

ENGINEERING ECONOMY - ANSWER 7.1 : By induction, the future value for 5 year = FV = PV (1 + i) (1 + i) (1 + i) (1 + i)(1 + i) = $1000 (1.06) (1.06) (1.06) (1.06)(1.06) = $1338.2256. The answer is given by Kang Chuen Tat; PO Box 6263, Dandenong, Victoria VIC 3175, Australia; SMS +61405421706; chuentat@hotmail.com; http://kangchuentat.wordpress.com.

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