Answer / sethu

L = L1 + L2 ± 2M.
When ordinary, L = L1 + L2 + 2M
∴ 40 = 10 + 15 + 2M.
∴ 2M = 15 mH
When opposing, L = L1 + L2 – 2M
= 10 + 15 – 15 = 10 mH

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