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The coils having selfinductancs 10mh and15mh,effective inductance 40mh when connected in series aiding. what will be the equivalent inductance if we connect them in series opposing?
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Answer / sethu
L = L1 + L2 ± 2M.
When ordinary, L = L1 + L2 + 2M
∴ 40 = 10 + 15 + 2M.
∴ 2M = 15 mH
When opposing, L = L1 + L2 – 2M
= 10 + 15 – 15 = 10 mH
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