Answer / viswa

To put it simply, for example in a closed loop system the measured value is sent back to the comparator to compare the value with the set point where as in open loop it is not.

what is the difference between car seal close/open valves and lock close/open valves?

0 Answers   MNC,

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What are the three classes of organic solvents?

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ACCOUNTING AND FINANCIAL ENGINEERING - EXAMPLE 34.17 : In the engineering calculations of interest rate caused by inflation, General Inflation Effect and Fisher Effect may be considered. Let I = inflation rate, R = nominal interest rate, r = real interest rate. According to Fisher Effect, (1 + R) = (1 + r) (1 + I). According to General Inflation Effect, r = R - I. (a) If I = 0.1 for all effects, both the values of R and r in the Fisher Effect are the same as R and r in the General Inflation Effect, find the values of R and r. (b) If R has the same value caused by both General Inflation Effect and Fisher Effect, find the possible values of R, r and I in term of R etc.

1 Answers  

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ACCOUNTING AND FINANCIAL ENGINEERING - EXAMPLE 34.30 : A biochemical engineering sales contract adopts Cost Recovery Method in its company accounting. Gross profit is realised only when cash collections exceed the total cost of goods sold. Let Y = Original Cost Recovered, Z = Gross Profit Realised. Its property was sold at A = $500k with cost of B = $300k. Its engineering accountant receives cash of C = $240k in first year, D = $180k in second year and E in third year. (a) Find the values of Y and Z in : (i) first year; (ii) second year; (iii) third year. (b) What is the exact value of E if all cash has been fully received from sales?

1 Answers  

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ENVIRONMENTAL ENGINEERING - QUESTION 22.2 : Biochemical Oxygen Demand (BOD) could be calculated using the formula BOD = (DOi - DOf) (Vb / Vs) where Vb = Volume of bottle in ml, Vs = Volume of sample in ml, DOi = Initial dissolved oxygen in mg / L, DOf = Final dissolved oxygen in mg / L. (a) By using a bottle of Vb = 300 ml with sample Vs = 30 ml, find the BOD if DOi = 8.8 mg / L and DOf = 5.9 mg / L. (b) By using a bottle Vb = 600 mL with sample Vs = 100 mL, find the BOD if DOi = 8.8 mg / L and DOf = 4.2 mg / L. (c) Find the average BOD = [ Answer of (a) + Answer of (b) ] / 2. (d) If the BOD-5 test for (a) - (c) is run on a secondary effluent using a nitrification inhibitor, find the nitrogenous BOD (NBOD) = TBOD - CBOD. Let TBOD = 45 mg / L and CBOD = Answer of (c).

1 Answers  

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what is density

2 Answers   CPCL, TII,

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what are the major problem comes in the production process

2 Answers   Atul, Deepak Fertilisers,

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What does capacitor load means? How does it connect?

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What is the order of a chemical reaction, , if the rate of formation of 'C', increases by a factor of 2.82 on doubling the concentration of 'A' and increases by a factor of 9 on trebling the concentration of 'B'?

0 Answers  

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what are the reaction between sodium meta bi sulphate and chlorine?

1 Answers   Dalkia,

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what is the difference between PFR ,MFR and batch rector

1 Answers   BARC, CPCL,

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we have 2 O2/Comb Analyzers Servomex Model 2700 in service for one of the furnaces in our chemical plant. It is giving High Temperature Alarm. Checked Temperature and found it to be 800 Deg C whereas Set Point is 700 Deg c. It is strange why is temperature not at SP. Also response is 23 % with 21 % Inst Air and with N2 reading is not coming down. please clarrify this issuses very urgent

1 Answers  

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