Answer / lalit

consider a nominal mix
1:4:8
cement:sand:coarse aggregate(the above nominal mix is always per volume)
now let's consider depth of roof as 1 feet.
now 1 bag of cement=1.25 cubic feet.
so let's cement volume is x,
then sand=4x and coarse aggregate=8x
now,
x+4x+8x=3200*1 cubic feet
find x,now from this value find out the no. of cement bags by dividing x by 1.25(of each bag)

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The company is following same question pattern and giving same questions in all year for all batches from the starting of company they didnt even able to frame new question,,so guys if u want to place in cccl just mail me i will send the questions....ramyakvb@gmail.com....if u mug all those answers u will be selected no proper selction procedure is considered so it is better to place in some other company...All The best dont attend cccl

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