How do we get this formula Ast=(0.5Fck/Fy) into(1-(in sqrt(1-((4.6Mu)/Fck.bd^2))

How do we get this formula Ast=(0.5Fck/Fy) into(1-(in sqrt(1-((4.6Mu)/Fck.bd^2))into bd
Fck=grade of cement i.e M25, M20
Fy=grade of steel i.e.Fe415,Fe250
Mu=moment
b=width
d=depth

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How do we get this formula Ast=(0.5Fck/Fy) into(1-(in sqrt(1-((4.6Mu)/Fck.bd^2))into bd Fck=grade o..

Answer / madan

M.R = 0.87 fy Ast d[1-(fyAst)/(fckbd)]
Use this formula to calculate Ast . Or u can generally solve this formula to get the equation in your question.
M.R=Moment of Resistance
Other notations are as usual.

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