Answer / brijesh

Because Steam density changes with change in its temperature
and pressure. So to get the correct mass flow you need to
introduce its temperature and pressure in the calculation.

Answer / sushil d. jambhulkar

THERE IS A EFFECT OF STEAM PRESSURE & STEAM TEMPERATURE ON
STEAM FLOW. TO COMPENSATE THIS EFFECT IT IS NECESSARY TO
TAKE STEAM TEMP & STEAM PRESSURE AS A REFERENCE.

Answer / sreeharsha

Generally flow measured will be represented as -- m3/sec at
NTP or STP i.e with reference to temperature and pressure,
so if don't consider temperature and pressure at which we
are measuring flow it may lead to erroneous value.

Answer / jo

its simple when the temprature increses the pressure will
be decreses and pr increases temp: decreses. there was a
relation between pr & temp, due to this may effect the flow
of steam.. means velocityof steam may decreses or increases
due to the pr. variation.

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Q1: Consider part of a control loop, which excludes the transmitter, consisting of a process, a controller and a control valve which may be represented by two dead times of 0.5 min each and three exponential lags of 0.8 min., 1.0 min. and 1.5 min. respectively. We wish to express this system as an overall first order plus dead time (FOPLD) model ie gain, time constant and process dead time. (We will see later that this is often done, to simplify controller tuning). For this exercise, gain is considered to be 1.0. (A) If the transmitter is a flow transmitter whose behaviour can be described by a dead time of 0.2 min. and an exponential lag of 0.5 min. in terms of the overall dead time and overall first order lag how can the system behaviour be approximated ? Overall dead time = Overall time constant = (B) If the transmitter is a temperature transmitter with a temperature sensor in a protecting well whose behaviour can be described by a dead time of 0.7 min. and an exponential lag of 15 min. how can the overall system behaviour be approximated now? Overall dead time = Overall time constant =

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