Answer / raghuram

#include<iostream.h>
#include<conio.h>
/*no. of 1's in no. of 1's steps*/
int count(unsigned long int n)
{
int count=0;
while(n)
{
count++;
n=n&n-1;
}
return count ;
}

Answer / vijay

#include<stdio.h>
main()
{
int x=123,i=0;
while(x)
{
x=x&(x-1);
i++;
}
printf("Number of set bits are %d \n",i);
}

Answer / xyz

main()
{
int i=1177;
int j=0;
while(i>0)
{
if((i%2)!=0)
j++;
i=i/2;
}
printf("The number of one is %d\n", j);
}

Answer / lawrence

@Turk
your solution is O(n) not O(logn). your algorithm still
counts each zeros and ones.

Answer / sunny arora

/* This is a table which will contain number of ones
corrosponding to number value */
static int bits_in_char [256] ;

int bitcount (unsigned int n)
{
// works only for 32-bit ints

return bits_in_char [n & 0xffu]
+ bits_in_char [(n >> 8) & 0xffu]
+ bits_in_char [(n >> 16) & 0xffu]
+ bits_in_char [(n >> 24) & 0xffu] ;
}

Answer / turk

Here is an O(logn) solution

#include<stdio.h>

int numberOfOnesByte(unsigned char c, int length){
if (c==0)
return 0;
if (c==1)
return 1;
unsigned char left, right;
int lengthP = length/2;
left = c>>lengthP;
right = c-(left<<lengthP);
return numberOfOnesByte(left,length-lengthP)+numberOfOnesByte(right,lengthP);
}
int numberOfOnes(unsigned char *array, int start, int end, int length){
if(length==1){
return numberOfOnesByte(array[start],8);
} else {
int lengthP = length/2;
return numberOfOnes(array,start,start+lengthP-1,lengthP)+
numberOfOnes(array,start+lengthP,end,length-lengthP);
}
}
int main(){
unsigned char array[8] = {0xFF,0XAA,0xFF,0XAA,0xFF,0XAA,0xFF,0XAA};
printf("number of bits %d\n",numberOfOnes(array,0,7,8));
return 0;
}

Answer / pgmrsf

static void NumOfOnes(uint n)
{
int c = 0;
for (int i=0; i<10; i++)
{
if ((n & (int)Math.Pow(2, i)) == (int)Math.Pow(2,
i))
{
c++;
}
}
Console.WriteLine("{0}", c);
}

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1 Answers  

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source code for delete data in array for c

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write a program in c to merge two array

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6 Answers  

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Is the following code legal? struct a { int x; struct a b; }

1 Answers  

I need your help, i need a Turbo C code for this problem.. hope u'll help me guys.? Your program will have a 3x3 array. The user will input the sum of each row and each column. Then the user will input 3 values and store them anywhere, or any location or index, temporarily in the array. Your program will supply the remaining six (6) values and determine the exact location of each value in the array. Example: Input: Sum of row 1: 6 Sum of row 2: 15 Sum of row 3: 24 Sum of column 1: 12 Sum of column 2: 15 Sum of column 3: 18 Value 1: 3 Value 2: 5 Value 3: 6 Output: Sum of Row 1 2 3 6 4 5 6 15 7 8 9 24 Sum of Column 12 15 18 Note: Your program will not necessary sort the walues in the array Thanks..

0 Answers  

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1 Answers   HCL,