Give a very good method to count the number of ones in a 32
bit number.
(caution: looping through testing each bit is not a solution)
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Answer Posted / raghuram
#include<iostream.h>
#include<conio.h>
/*no. of 1's in no. of 1's steps*/
int count(unsigned long int n)
{
int count=0;
while(n)
{
count++;
n=n&n-1;
}
return count ;
}
| Is This Answer Correct ? | 41 Yes | 26 No |
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