how can change 10mm dia @130c/c bar spacing to 8mm dia
Answers were Sorted based on User's Feedback
Answer / shanker singh devera
(d1)^2/spacing = (d2)^2/spacing
(10^2)/130 =(8^2)/x
100/130=64/x
0.7694=64/x
x=64/0.7694 =83.2
Ans=83.2 spacing
Is This Answer Correct ? | 95 Yes | 9 No |
Answer / j.saminathan
(spacing/wt.of given rod)xwt.of rod to be changed=required
spacing
Is This Answer Correct ? | 14 Yes | 1 No |
Answer / esantharaj
spacing. =1000/130
=8 nos. 8*.617=4.93 kg
total wt/unitw.t. =4.93/.39
=12+1. =13nos
spacing=1000/13
=77mm
cross checking=13*.39=5.05 kg
Is This Answer Correct ? | 3 Yes | 2 No |
Answer / rajesh kumar jha
spacing = ast/Ast
130 = 8*8 / Ast
Ast =64 / 130
Ast = 0.492 then after
spacing = ast / Ast
= 10*10 /0.4925
= 203
spacing = 200
ASt = area of steel
ast = area of bar
Is This Answer Correct ? | 16 Yes | 16 No |
Answer / bkb
Hii Every one,
any one know in which IS code mention below formula-
(d1)^2/spacing = (d2)^2/spacing
Is This Answer Correct ? | 0 Yes | 0 No |
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